安卓 如何在按钮正上方显示弹出窗口

Question

I need to show popup window directly above button. My button is placed inside scroll view, and popup always shown below button. Here is my code:

  private void showPopup(View view, String text) {
    if (infoPopup == null) {
        LayoutInflater layoutInflater = LayoutInflater.from(getActivity());
        View popupView = layoutInflater.inflate(R.layout.popup_credit_request_passport, null);
        TextView tvPopupText = popupView.findViewById(R.id.tv_popup_text);
        tvPopupText.setMovementMethod(new ScrollingMovementMethod());
        tvPopupText.setText(text);
        FrameLayout flBackground = popupView.findViewById(R.id.fl_background);
        flBackground.setBackground(new BubbleDrawable(getContext(), R.color.azure, 16, 16, 8));

        infoPopup = new PopupWindow(popupView,
                ViewGroup.LayoutParams.MATCH_PARENT,
                ViewGroup.LayoutParams.WRAP_CONTENT);
        infoPopup.setBackgroundDrawable(new ColorDrawable(Color.TRANSPARENT));
        infoPopup.setOutsideTouchable(true);

        infoPopup.showAtLocation(view, Gravity.TOP, (int) view.getX(), (int) view.getY());

    } else {
        dismissInfoPopup();
    }
}

But it is not work. Please hep me.

Answer 1

将“ 重力”更改为“顶部”，然后根据需要重置坐标。

infoPopup.showAtLocation(view, Gravity.TOP, 0, (int) view.getY());

Answer 2

当您必须显示弹出窗口时，找出按钮在屏幕上的位置，然后使用Gravity.TOP和按钮在屏幕上的x,y coordinates ，如Prachi Said一样使用Gravity.TOP showAtLocation()方法...