[英]Count separate row on same id from different table : MySQL
I want to count the number of aircon and client under the same usr_id
. 我想计算同一
usr_id
下的usr_id
和client的usr_id
。 Here's my resources: 这是我的资源:
clients_db clients_db
+---------+--------+
| clnt_id | usr_id |
+---------+--------+
| 1 | a1 |
+---------+--------+
| 2 | a1 |
+---------+--------+
| 3 | a2 |
+---------+--------+
| 4 | a1 |
+---------+--------+
aircon_client_db aircon_client_db
+---------+--------+---------+
| ac_id | usr_id | clnt_id |
+---------+--------+---------+
| 1 | a1 | 1 |
+---------+--------+---------+
| 2 | a2 | 2 |
+---------+--------+---------+
| 3 | a2 | 1 |
+---------+--------+---------+
| 4 | a2 | 3 |
+---------+--------+---------+
According to the tables above. 根据上表。 I want to count
我要数
clnt_id
under the same usr_id
clnt_id
相同下usr_id
ac_id
under the same usr_id
ac_id
相同下usr_id
So I coded: 所以我编码:
select count(acdb.ac_id) as nAC,
count(clnt.clnt_id) as nClnt
from aircon_client_db acdb
left join clients_db clnt on clnt.usr_sid=acdb.usr_sid
where acdb.usr_sid='a1'
I expect the answer as following: 我期望答案如下:
But as I tested. 但是正如我测试过的那样。 My results are the same for both count - 4. Where did I wrong?
我的结果在两个方面都是相同的-4.我在哪里弄错了?
You want to count: 您要计算:
clnt_id
s from the table clients_db
and clnt_id
从表S = clients_db
和
ac_id
s from the table aircon_client_db
表
aircon_client_db
ac_id
s
for usr_sid='a1'
, right? 对于
usr_sid='a1'
,对吗?
I don't see the necessity of joining the tables. 我认为没有必要加入表格。
You can count separately with 2 subqueries in the same query: 您可以在同一查询中使用2个子查询分别计数:
select
(select count(ac_id) from aircon_client_db where usr_sid = 'a1') as nAC,
(select count(clnt_id) from clients_db where usr_sid = 'a1') as nClnt
If there is a case of duplicate clnt_id
s in clients_db
or duplicate ac_id
s in aircon_client_db
, then use: 如果有重复的情况下
clnt_id
S IN clients_db
或重复ac_id
S IN aircon_client_db
,然后使用:
count(distinct clnt_id)
and count(distinct ac_id)
count(distinct clnt_id)
和count(distinct ac_id)
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.