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如何使用2种类型的JSONObject解析JSONArray?

[英]how to parse JSONArray with 2 type of JSONObject?

I'm trying to parse this JSONArray that has 2 different types of JSONs. 我正在尝试解析这个有两种不同类型JSON的JSONArray。 {"key":"a","value":"b"} and {"key":"c"} . {"key":"a","value":"b"}{"key":"c"} i don't know the order of these JSONs in JSONArray; 我不知道JSONArray中这些JSON的顺序; it could be something like this: [{"key":"a","value":"b"},{"key":"c"},{"key":"d","value":"e"}] . 它可能是这样的: [{"key":"a","value":"b"},{"key":"c"},{"key":"d","value":"e"}]

how can i parse this JSONArray? 我怎么解析这个JSONArray?

You can actually do something like this 你实际上可以做这样的事情

JSONArray arr = new JSONArray(
                "[{\"key\":\"a\",\"value\":\"b\"},{\"key\":\"c\"},{\"key\":\"d\",\"value\":\"e\"}]");
        for (int i = 0; i < arr.length(); i++) {

            JSONObject obj = (JSONObject) arr.get(i);
            Iterator<String> keys = obj.keys();
            while (keys.hasNext()) {
                String key = keys.next();
                //your logic for checking if object has both keys or one key goes here
                if (key.equals("key")) {

                }
            }

        }

You can use JSON.simple to convert string data to JSON array. 您可以使用JSON.simple将字符串数据转换为JSON数组。 https://mvnrepository.com/artifact/com.googlecode.json-simple/json-simple/1.1.1 https://mvnrepository.com/artifact/com.googlecode.json-simple/json-simple/1.1.1

public static void main(String[] args) throws ParseException {

    String data = "[{\"key\":\"a\",\"value\":\"b\"},{\"key\":\"c\"},{\"key\":\"d\",\"value\":\"e\"}]";

    JSONParser parser = new JSONParser();

    JSONArray jsonArray = (JSONArray) parser.parse(data);

    for (Object obj : jsonArray) {
        JSONObject jsonObject = (JSONObject) obj;

        //Verify json type by checking for value

        if (jsonObject.get("value") == null) {
            // Type 1 key
            System.out.println(jsonObject.toJSONString());
        } else {
            // Type 2 key and value
            System.out.println(jsonObject.toJSONString());
        }
    }
}

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