Java脚本输入格式验证

Question

I wanted to validate the below format of one of the input fields

1111-111-111 //4digits- 3digits- 3digits

I tried the below method but its not working. Any idea of what am I misisng?

function(value) {
    var patt = "/^\d{4}-d{3}-d{3}$/";
    var res = value.match(patt);
    if (!res) {
        return {
            status: 2,
            message: 'Input should be formatted as 0000-000-000'
        };
    } else {
        return {
            status: 0
        };
    }
}

Also, given a string, I wanted to enforce characters at certain indices are empty. like for eg: 23 total characters, where 2nd, 9th, 11th and 13-21 are space characters. I am new to Javascript regex, how do we enforce these?

Answer 1

Your regular expression is wrong. Fix it:

/^\d{4}-\d{3}-\d{3}$/

Your second part and third part are "d" characters, not numbers. And remove the " characters when declare a regex.

var patt = /^\d{4}-\d{3}-\d{3}$/;

Answer 2

If we only wish to pass 4-3-3 digits, we could simply do that using:

^[0-9]{4}-[0-9]{3}-[0-9]{3}$

Demo

or:

^\d{4}-\d{3}-\d{3}$

Demo

If we wish to also capture the phone number, we would be adding a capturing group:

^([0-9]{4}-[0-9]{3}-[0-9]{3})$

 const regex = /^[0-9]{4}-[0-9]{3}-[0-9]{3}$/gm; const str = `1111-111-111 1111-111-1111 8888-888-888`; let m; while ((m = regex.exec(str)) !== null) { // This is necessary to avoid infinite loops with zero-width matches if (m.index === regex.lastIndex) { regex.lastIndex++; } // The result can be accessed through the `m`-variable. m.forEach((match, groupIndex) => { console.log(`Found match, group ${groupIndex}: ${match}`); }); } 

RegEx Circuit

jex.im visualizes regular expressions:

Answer 3

The first pattern does not work like intended because to match a digit you have to escape the d like \\d or else d{3} would match 3 times a d character and the pattern should not be between double quotes but between / ... /

 let test = function(value) { var patt = /^\\d{4}-\\d{3}-\\d{3}$/; var res = value.match(patt); if (!res) { return { status: 2, message: 'Input should be formatted as 0000-000-000' }; } else { return { status: 0 }; } }; console.log(test("1111-111-111")); 

For matching spaces at the places 2nd, 9th, 11th and 13-21 in the string you could use quantifiers and \\S to match a non whitespace character:

^\S \S{6} \S \S {11}$

Regex demo

If you want to match by index based on a zero index, the pattern would look like:

^\S\S \S{6} \S \S {10}$

Regex demo