如何在LLDB中逐步进入最外部的函数调用？

Question

Let's say I'm debugging code like this

   outer(fn1(), fn2());

If I use the s command, LLDB will first step into fn1 , then I type fin to step-out, s again steps into fn2 , fin ... and only now I'm able to step-into outer which is what I wanted since the beginning.

Is there a way to tell LLDB on which function call to step-in?

Answer 1

thread step-in --step-in-target outer or more compactly, s -t outer will stop when it has stepped into outer . See help s for the documentation.

Answer 2

lldb comes with an alias for exactly this: sif . In the given example, you can run:

(lldb) sif outer

You can remember it as s tep i nto f unction

It works with partial matches, it doesn't have to be called with the full function name. In this case, you could also run sif out for example.

Answer 3

直接不是。但是您可以在外部函数的定义中设置断点。