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如何在 flutter 中将字符串列表转换为字符串?

[英]How to convert String List to String in flutter?

I need to convert List<String> into a String in the dart.我需要将List<String>转换为 dart 中的String

I want to extract the value of the list from preferences.我想从首选项中提取列表的值。 I have tried this implementation but it is only giving me the last value.我已经尝试过这个实现,但它只给了我最后一个值。

Future<List<String>> services = SharedPrefSignUp.getSelectedServices();
services.then((onValue){
  List<String>servicesList=onValue;
  selectServicesText=servicesList.join(",");
});

if you know you have List<String> then you can use join() function provided by a flutter.如果你知道你有List<String>那么你可以使用 flutter 提供的join()函数。

    var list = ['one', 'two', 'three'];
    var stringList = list.join("");
    print(stringList); //Prints "onetwothree"

Simple and short.简单而简短。 ;) ;)

And you can use it like this:你可以像这样使用它:

 List<String>servicesList=["one", "Two", "Thee"]; 
 print(servicesList.join(""));

You can iterate list and concatenate values with StringBuffer您可以使用 StringBuffer 迭代列表和连接值

  var list = ['one', 'two', 'three'];
  var concatenate = StringBuffer();

  list.forEach((item){
    concatenate.write(item);
  });

  print(concatenate); // displays 'onetwothree'

  }

You can use reduce method on a list like that:您可以在这样的列表上使用reduce方法:

List<String> list = ['one', 'two', 'three'];
final string = list.reduce((value, element) => value + ',' + element);

// For your example:
List<String> servicesList = await SharedPrefSignUp.getSelectedServices();
selectServicesText = servicesList.reduce((value, element) => value + ',' + element);

If you want to convert your List<String> to a coma septated String , you can do this如果要将List<String>转换为coma septated String ,则可以执行此操作

 List<String> list =["one", "Two", "Thee"];
 print(list.join(","));  // Output will be like this : one,Two,Thee

Join() method Converts each element to a String and concatenates the strings. Join()方法将每个元素转换为字符串并连接字符串。

Just in case someone wants to concatenate specific member strings in a list of objects: here is a way to do the same-以防万一有人想在对象列表中连接特定的成员字符串:这是一种方法 -

   string commaSeparatedNames=return listOfObjectsWithNameAttribute
      .map((item) => item.name)
      .toList()
      .join(",");
 print(list.toString().replaceAll('[', '').replaceAll(']',''))

if you need just first word to be highlighted use this如果您只需要突出显示第一个单词,请使用此

 import 'package:flutter/material.dart'; class TextHighlight extends StatefulWidget { final String text; TextHighlight({ required this.text, }); @override State<TextHighlight> createState() => _textHighlightState(); } class _textHighlightState extends State<TextHighlight> { String first = ''; List<String> allText = []; List<String> newText = []; @override Widget build(BuildContext context) { first = widget.text.split(' ').first; allText = widget.text.split(' ')..removeAt(0); return RichText( text: TextSpan( children: [ TextSpan(text: first+' ', style: TextStyle(color: Colors.green, fontSize: 17)), TextSpan(text: allText.join(' ').toString(), style: TextStyle(color: Colors.black)), ], ), ); } }

@nivia360 its work for me! @nivia360 它为我工作!

The problem is cant eliminate the bracket to the list of array.问题是无法消除数组列表中的括号。 this code movie.tags.toString(), Return this list whit brackets此代码movie.tags.toString(),返回此列表带括号
[Adventure, Fantasy, Action]

I soved how the @nivia360 propouse usingn我解决了@nivia360 如何使用

movie.tags.toString().replaceAll('[', '').replaceAll(']', ''),

Problema问题

Solution解决方案

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