如何在一定数量的非空格和非段落字符后拆分文本？

Question

I would like to split up a text after a certain number of non-space and non-paragraph characters.

So far, I know that you can do this to split up a string after a total number of characters

cutOff = 10
splitString = oldString[0:cutOff]

But how do I do this so that it does not factor spaces in the character count?

Answer 1

You can do a while loop.

oldString = "Hello world"
cutOff = 10

i = 0
while i < cutOff and cutOff < len(oldString):
    if oldString[i] in [' ', '\n']: cutOff += 1
    i += 1

splitString = oldString[:cutOff]

Answer 2

You can use a regular expression. This returns a two-element tuple (list) containing the two halves of the input string broken at the desired location:

import re

data = """Now is  the time
for all   good men
to come"""

def break_at_ignoring_whitespace(str, break_at):
    m = re.match(r"((\s*\w){%d})(.*)" % break_at, str, re.S)
    return (m.group(1), m.group(3)) if m else (str, '')

r = break_at_ignoring_whitespace(data, 14)

print(">>" + r[0] + "<<")
print(">>" + r[1] + "<<")

Result:

>>Now is  the time
fo<<
>>r all   good men
to come<<