正则表达式与Scala代码中的字符串不匹配

Question

This Regex is not working for below given string, as below string has “href”. I am using scala 2.11.11

val p1 = Pattern.compile("href=\"(.*?)\"")
    val m1 = p1.matcher(bodyString)
    while(m1.find()){
        println(m1.group(1))
    } 

String:

"<p>Is this person trying to advertise a sound card? They dont seem to be answering my questions either </p><p><br /></p><p><a href=\"https://discussion.xyz.com/thread/2524?answerId&#61;25022&amp;page&#61;1\" target=\"_blank\" rel=\"nofollow opener referrer\">https://discussion.xyz.com/thread/250274?answerId&#61;250722&amp;page&#61;1</a></p>"

Please suggest if any other way to do this.

Thanks

Answer 1

Your expression seems to be fine, there are just two backslashes in the input string that can be likely included, maybe in this form:

href=\\\"(.*?)\\\"

Demo 1

or if we'd be searching for https patterns, we could simplify it to:

\\"https?:(.*?)\\"

Demo 2

and our desired link is in the capturing group #1 .

RegEx

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