取两个mathrandom值并将它们添加到循环中

Question

I have to make a game of dice where I add the values of both the dice and give the sum. You get another turn if both the dice end up on the same number (such as 2 and 2 which is 4) then you roll the dice again and the 2 new numbers get added to the previous sum (like 4 mentioned earlier). For example - 1st try 3 and 3, sum is 6. 2nd try 4 and 5, sum is 6 + 4 + 5 = 15

I'm able to get the first sum right, but the subsequent numbers are getting messed up sometimes even giving twice as much.

function oneRandom(){
    var my1 = Math.floor(Math.random() * 6 ) +1 ;   
    var my2 = Math.floor(Math.random() * 6 ) +1 ;
     var num1 = Number(my1);
    var num2 = Number(my2);

    var sum = num1 + num2;
    console.log(sum);
    var resultfield = document.getElementById("total").innerHTML = "<h1>"+sum+"</h1>";

    document.getElementById("cilc").style.display = "none";
    if (getImage.src == get2.src){
        document.getElementById("cilc").style.display = "block";
        var sum2 = num1 + num2;
        var total = sum2 + sum;
    var resultfield = document.getElementById("total").innerHTML = "<h1>"+total+"</h1>";
    }

}

The getImage and get2 are arrays to match dice images to give another turn in case of same numbers loading.

Answer 1

You can try this,

 function rollDice (times) { var num1 = Math.floor(Math.random() * Math.floor(6)); var num2 = Math.floor(Math.random() * Math.floor(6)); console.log(times, num1, num2); var total = num1 + num2; return num1 === num2 ? total + rollDice(times + 1) : total; } console.log(`result is ${rollDice(0)}`);