使用方括号的熊猫基础知识

Question

As seen by the code, I am trying to print out my table from the intervals of 0 to when hr1 in the column time is first equal to 1: 01 ( or 1:01 am). I am having a problem with how to implement when hr1 is equal to 1:01 in the square brackets.

import pandas as pd 

table = pd.read_csv('2019-01-20.csv')
speed = table['speed_mph']
time = table['timestamp']
x = 1

for hr1 in time: 
  if x < 2: 
    print(table[0:(hr1='1:01')])
    x += 1

Answer 1

Simplest would be to use index to find the first element equal to 1.01

print(table[0:time.index('1:01')+1])

I've added one to the result of the index() call to include that element. Note that if '1.01' is the last element in the list, this will yield an IndexError .

If the element is not found index() will raise a ValueError .

Note also that you should not use time as a variable name, as this shadows the python built-in module of the same name.

I second the comment above, as well. Simply guessing at what the syntax might be will cause a lot of wasted time. You may also find that you get something working by accident, which later on fails with a different data-set.

Answer 2

table.iloc[:table[table.timestamp == 'your timestamp'].index[0] + 1]

iloc切片索引，table [table.timestamp =='your timestamp'] .index [0]返回第一个匹配的索引，+ 1将其包含在结果中。