如何从字母数字字符串中提取有效数字？

Question

I have an ID DIS002789.I want to extract 2789 from the given ID.I have to use the extracted number in a for loop using a variable.

I tried using re.findall.

inputk='DIS0002789'
non_decimal = re.findall(r'[\d.]+', inputk)
for n in range(non_decimal, non_decimal + 1000):

Im getting 002789. But I want my output to be 2789.And also i cant use the for loop because of this.It shows an error saying 002789 is an invalid syntax. I tried converting it to int. but its shows the following error, TypeError: int() argument must be a string, a bytes-like object or a number, not 'list'

Answer 1

you can pass the result of re.findall(r'[\\d.]+', inputk) to int in order to make it an integer. int('0123') will ignore leading zeroes.

Example:

inputk='DIS0002789'
non_decimal = int(re.findall(r'[\d.]+', inputk))

if you want it to be a string you can pass it to str again: str(int('0123')) == '123'

Answer 2

If you want the int value, you should convert it to integer as other answers show. If you only want the string, you can try adding the optional leading zeros:

inputk='DIS0002789'
non_decimal = re.findall(r':?[0]*(\d+)', inputk)
non_decimal

output:

['2789']

Answer 3

you can ignore leading zeros and convert it to an integer to use in a loop

inputk='DIS0002789'
non_decimal = int(re.findall(r':?[0]*(\d+)', inputk)[0])