[英]Undefined Reference to “typeinfo for <class>”
I saw questions about this problem but i can't find any solutions working for me. 我看到了有关此问题的问题,但找不到适合我的解决方案。 I am using Visual Code with C++ and C++ version is anterior to C++ 11. I have DNS classes, with various classes inheriting a principal DNS message class, this way I can factorize some attributes. 我将Visual Code与C ++一起使用,并且C ++版本早于C ++11。我有DNS类,各种类继承了主要的DNS消息类,这样我就可以分解某些属性。 In function of the type type field I can know the type of the object. 在类型类型字段的功能中,我可以知道对象的类型。 When I compile I have an error "undefined reference to "typeinfo for DNS_RR_A" for example, but I got this at each dynamic cast I am doing to check the class of the object. 例如,当我编译时,出现错误“对“针对DNS_RR_A的typeinfo的未定义引用””,但是我在每次动态转换时都得到了此信息,以检查对象的类。
My dnsMessage.cpp only have constructor and destructor. 我的dnsMessage.cpp只有构造函数和析构函数。
here is my classes: 这是我的课程:
class CDnsMessage
{
public:
CDnsMessage();
virtual ~CDnsMessage();
virtual void GetSize() = 0;
uint32_t m_ttl;
eDnsClass m_class;
eDnsType m_type;
std::string m_domain;
uint8_t m_sizeDnsCorpse;
uint8_t m_sizeDomainName;
};
class CDns_RR_A : public CDnsMessage
{
public:
CDns_RR_A();
virtual ~CDns_RR_A();
virtual void GetSize() {/*....*/}
uint32_t m_address;
};
And here is a sample of my function using with the error at the dynamic cast. 这是我的函数示例,在动态转换时使用了错误。 I receive a message I have to encode but I don't know the nature of the message so I dynamic cast so I can adapt my encode: 我收到了我必须编码的消息,但我不知道消息的性质,因此我进行了动态投射,因此可以调整编码:
//i receive a message i have to encode, i don't know the type
void EncodeOpaqueData(CDnsMessage & msg, std::vector<uint8_t>& output)
{
//where i encode
output.clear();
// Error : "undefined reference to `typeinfo for CDns_RR_A'"
if(dynamic_cast< CDns_RR_A* >( &msg ) != NULL)
{
CDns_RR_A* RR_A_msg = dynamic_cast< CDns_RR_A* >( &msg );
uint16_t dnstype = cmn_hton16(1);
output.push_back(dnstype);
output.push_back(dnstype >> 8);
/* stuff here */
uint32_t address = cmn_hton32(RR_A_msg->m_address);
for (int i = 0; i < 4; i++)
{
output.push_back(static_cast<uint8_t>(address >>(i * 8)));
}
}
}
After think more of the function, instead of checking the type of the object I could check msg->m_type and adapt in function of the type, the m_type variable can be wrongly instantiated for example. 在考虑了更多的功能之后,除了检查对象的类型,我可以检查msg-> m_type并适应类型的函数,例如,可以错误地实例化m_type变量。 But anyway I would like to understand this error and how to fix it. 但是无论如何,我想了解这个错误以及如何解决。 thanks in advance. 提前致谢。
Try to change the reference parameter to a pointer like this: 尝试将参照参数更改为这样一个指针:
void EncodeOpaqueData(CDnsMessage * msg, std::vector<uint8_t>& output)
You have the explanation here: 您在这里有解释:
Difference in behavior while using dynamic_cast with reference and pointers 将dynamic_cast与引用和指针一起使用时行为上的差异
The class impedimenta—virtual method table and typeinfo—are generated when the first declared virtual method is compiled. 当编译第一个声明的虚拟方法时,将生成impedimenta类(虚拟方法表和typeinfo)。 Are you defining the virtual ~CDnsMessage();
您是否正在定义 virtual ~CDnsMessage();
(ie CDnsMessage::~CDnsMessage() {}
) and is the file where it is defined included in the link. (即CDnsMessage::~CDnsMessage() {}
),并且是链接中包含该文件的定义文件。
Note that out-of-line definitions are not weak, so it must be defined in exactly one source (not header) file. 请注意,离线定义并不弱,因此必须在一个源文件(而不是标头文件)中定义它。
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