MySQL 5.7仅比较混合VARCHAR列中的数字

Question

NOTE: Please note this is NOT the same as similarly titled questions (see "What I've Tried", below)

Background:

I need to search a database string column for a phone number that matches a given search criteria.

The database column is a varchar with various user supplied additional (ie non-numeric) characters.

My original idea was to use a system to convert the column string to a numeric only format (in PHP this would be via PCRE functions) and then do a straight indentical comparison

Example data held:

 id telephone: ---------------------- 1 '01576 456 567' 2 '07768345998' 3 '+447588 43 34 56' 4 '01524-901-335' 

There are a variety of human readable formats held, these are submitted by the end user and are often historic.

Problem:

I can not find a way to search this column for a number. I have stripped down the search field in PHP to number only (0-9). I want to try something like:

"Search the telephone column and find where the numeric ONLY value (from a mixed string) matches the given search string exactly.

(pseudo-code:)

  SELECT telephone, id FROM phones WHERE REGEX_REPLACE(`telephone`, '[^0-9]') = :searchNumber 

(:searchNumber is the PDO placeholder.)

Example Search Term:

"01576456567"

Expected output:

From entering the search term into the SQL query I want to be able to retrieve the id number. In the above search example; $result['id'] = 1;

Limitations:

This is on MySQL vesion 5.7 only. I can not use MySQL 8.0 here.

It would cause a lot of secondary work to convert the phone columns to numeric column types and we don't have the time flexibility to do this right now.

What I've Tried:

• The REGEXP type functions on MYSQL return true / false (0/1) rather than a REGEXP processed output string.

• CASE to SIGNED / UNSIGNED does not work because it breaks at any whitespace in the string and also can lop off the leading zero.

• I have read various MySQL Stack Overflow answers

Escape Clause:

If my query is confusing this PHP code may better example what I'm trying to achieve.

• If all else fails I can export all of the numbers and run them through a PHP loop which would do the same thing:

   $searchNumber = preg_replace('/[^0-9]/','',$searchNumberSource); foreach ($numberFromDb as $row){ if(preg_replace('/[^0-9]/',''.$row) === $searchNumberSource){ // Matching number is found. break; } } 

Answer 1

一个简单的方法是嵌套使用replace

select replace(replace(replace(telephone,' ',''), '-',''), '+','') 

Answer 2

You should fix the data so it matches how you want to use it. That may take some effort now, but fixing the data will simplify your code ongoing -- rather than having arduous work-arounds.

My suggestion is to make the change on the application side. Change the number to a regular expression:

SELECT telephone, id
FROM phones
WHERE telephone REGEXP :searchNumber_regex;

Then :searchNumber_regex for '"01576456567' would look like:

'^[^0-9]*0[^0-9]*1[^0-9]*5[^0-9]*7[^0-9]*6[^0-9]*4[^0-9]*5[^0-9]*6[^0-9]*5[^0-9]*6[^0-9]*7[^0-9]*$'

Basically, the pattern [^0-9]* is at the beginning and end and in-between every number.