str_replace 方法在 php 中不起作用

Question

I use str_replace and does not work properly. I have a QueryString I want to replace some of the words with the amount of input, but the str_replace method does not work and does not change anything.

$inputdata = json_decode(file_get_contents('php://input'), true);
$query2 = $inputdata["QueryString"] . $where . " ORDER BY "  .$inputdata["DataRequest"]["Sort"][0]["field"]." " .$inputdata["DataRequest"]["Sort"][0]["dir"]. " LIMIT ".$inputdata["DataRequest"][take]." OFFSET " .$inputdata["DataRequest"][offset];
for ($x = 0; $x < count($parameters); $x++) {

 $query2 = str_replace($inputdata["parameters"][$x][key],$inputdata["parameters"][$x][value],$query2);

}

query2 return :

" SELECT Members .*, HouseholdAdmin . AdminCode FROM Members JOIN HouseholdAdmin ON Members.HouseholdAdminId=HouseholdAdmin.HouseholdAdminId WHERE MemberId =%MemberId "

str_replace($inputdata["parameters"][$x][key],$inputdata["parameters"][$x][value],$query2); not work

$query2 = str_replace('%MemberId','2',$query2); not work.

$query2 = str_replace('SELECT','dsdfsdfsdf',$query2); not work.

$query2 = str_replace('anyThing','anyThing',$query2); not work.

,....

It does not matter which words I enter & replace in str_replace, nothing works.

Answer 1

$query2 = str_replace($inputdata["parameters"][$x][key],$inputdata["parameters"][$x][key],$query2); 

$query2 = str_replace('%MemberId','2',$query2); 

$query2 = str_replace('SELECT','dsdfsdfsdf',$query2);

$query2 = str_replace('anyThing','anyThing',$query2);