使用JavaScript删除屏幕大小低于某个像素的div

Question

I'm a newbie in coding. I knew this can be done by css, but want to do it by using JavaScript. I have a div tag and would like to not show it under 630px screen size. I searched this site and find this JavaScript code in another question and I liked it:

if( window.innerWidth > 630 ) {
//Your Code
}

But as I'm newbie I'm not familiar on how to insert it in my PHP code and where to insert div so it only works for screen above 630px.

Answer 1

Here is a way to hide a div when the width of the screen is smaller then 700px

 function myFunction(x) { if (x.matches) { // If media query matches document.getElementById("divIWantedToHide").style.visibility = "hidden"; } else { document.getElementById("divIWantedToHide").style.visibility = "visible"; } } var x = window.matchMedia("(max-width: 700px)") myFunction(x) // Call listener function at run time x.addListener(myFunction) 

 <div id="divIWantedToHide"> tset </div> 

Fiddle

Personally I would recommend you to use CSS for this to be more precise media querys.

 @media only screen and (max-width: 700px) { #divIWantedToHide { display: none; } } 

 <div id="divIWantedToHide"> tset </div> 

Fiddle

Answer 2

This is more of an event issue:

At the basic level, this is how you could toggle by resize event :

 var el = document.getElementById("yes"); //get the element node //target resize event window.onresize = function(){ //this will check everytime a resize happens if(window.innerWidth > 630) { //if width is still bigger than 630, keep the element visible el.style.display = "block"; //exit the funtion return; } //At this point, the width is less than or equals to 630, so hide the element el.style.display = "none"; } 

 <div id="yes"> Yey! I am visible </div>