简体   繁体   English

Java使用jsonpath从另一个Json创建一个新的Json读取

[英]Java create a new Json reading from another Json using jsonpath

In java (any library), starting from a json like the following (with nested fields, arrays and embedded documents): 在java(任何库)中,从json开始,如下所示(带有嵌套字段,数组和嵌入文档):

{
  "first" : "1",
  "second" : {
     "third" : "3",
     "fourth" : "4"
  },
  "fifth" : [
     {
        "index" : 0,
        "value": "something"
     },
     {
        "index" : 1,
        "value": "else"
     }
  ]
}

and then apply following jsonpaths (as example, ideally any kind of jsonpath) 然后应用以下jsonpaths(例如,理想情况下任何类型的jsonpath)

  • second.fourth
  • fifth[1].[*]

create a json document like the following: 创建一个如下所示的json文档:

{
  "second" : {
    "fourth" : "4"
  },
  "fifth" : [
     {
        "index" : 1,
        "value": "else"
     }
  ]
}

So the question is: it's possible to use jsonpath not only to get data but also all nested fields and create a new json as subset of input? 所以问题是:可以使用jsonpath不仅可以获取数据,还可以使用所有嵌套字段并创建一个新的json作为输入的子集?

Any example is appreciated like always 任何例子都像往常一样被欣赏

Note : after thinking a lot about this, I've come to conclusion that what I need is an implementation of $project from Mongodb, but in Java and without a database. 注意 :经过深思熟虑后,我得出结论,我需要的是Mongodb的$ project实现,但是在Java中没有数据库。

If you can use lodash, there is set and get function for objects. 如果你可以使用lodash,那么对象就有set和get函数。

var source = {
  "first" : "1",
  "second" : {
     "third" : "3",
     "fourth" : "4"
  },
  "fifth" : [
     {
        "index" : 0,
        "value": "something"
     },
     {
        "index" : 1,
        "value": "else"
     }
  ]
};

var destination = {};

var path = "second.fourth";

_.set(destination, path, _.get(source, path));

path = "fifth[0]";     //Drawback -> if use fifth[1], then destination.fifth will have 0th element empty and 1st element filled.

_.set(destination, path, _.get(source, path));

Else you will need to write the javascript for these set and get operator. 否则,您需要为这些set和get运算符编写javascript。

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM