从python中提取月份的最后一天和第一天

Question

i am new in python ,i have a string of this format

Ex. 'Mar-00'

how could i calculate first day and last day from this month.

OUTPUT :

first day : 01-Mar-00

last day : 31-Mar-00

ex : 'Feb-17'

first day : 01-Feb-17

last day : 28-Feb-17

Answer 1

you can use calendar.monthrange(year, month)[1] to get the number of days in a given month+year.

the first is alway 01, and last is the value of calendar.monthrange(year, month)[1]

try this, let me know if it works:

import calendar

month_abbr_to_num = {v: k for k,v in enumerate(calendar.month_abbr)}

month_abbr, year_2_digit = input("please enter month, e.g. Mar-00:  ").split('-')

month = month_abbr_to_num[month_abbr]
year = int('20'+year_2_digit)

days_in_month = calendar.monthrange(year,month)[1]

print("first day : {:02d}-{}-{}".format(1, month_abbr, year_2_digit))
print("last day : {:02d}-{}-{}".format(days_in_month, month_abbr, year_2_digit))

EDIT:

following your comment on original question, here it is in the form of a function that returns both as datetime objects:

import calendar
import datetime

month_abbr_to_num = {v: k for k,v in enumerate(calendar.month_abbr)}

def get_first_and_last_day(user_input):
    month_abbr, year_2_digit = user_input.split('-')
    month = month_abbr_to_num[month_abbr]
    year = int('20' + year_2_digit)
    days_in_month = calendar.monthrange(year, month)[1]
    first_day = datetime.datetime(year, month, 1)
    last_day = datetime.datetime(year, month, days_in_month)
    return first_day, last_day



first, last = get_first_and_last_day(input("please enter month, e.g. Mar-00:  "))

print("first day : ",first)
print("last day : ",last)