我的代码不允许一个字符出现 2 次（如何修复）

Question

I need to write a code that counts the amount of closed area's en the amount of ends within a word (so B has 2 closed area's) but when 1 character sits 2 times within 1 question it only counts 1 time.

I tried something that should count the amount of characters but that just gived me more errorzs

G = 0
Chosen_word = str(input("Choose a word of max 60 character(only uppercase)"))
if "A" in Chosen_word:
  U = U + 2
  G = G + 1

if you type AA it should print 4 ends en 2 closed area's but it prints 2 ends en 1 closed area

Answer 1

You're only going through this code once - for the first letter. To go through each letter , you need to use a loop (a for loop that goes through every character would be best here):

for letter in chosen_word:
    if letter == 'A':
        U = U + 2
        G = G + 1
    elif letter == 'B':
        ...

Answer 2

G = 0
U=0
Chosen_word = str(input("Choose a word of max 60 character(only uppercase)"))

n = Chosen_word.count("A")
U = n * 2
G = n 

print (U)
print (G)

OUTPUT:

Choose a word of max 60 character(only uppercase)SADDSAAAA
10
5