[英]Skips Elif Condition
during the execution of the code the program skips all ELIF conditions, going directly to ELSE, even if the ELIF condition is TRUE 在执行代码期间,程序跳过所有ELIF条件,直接进入ELSE,即使ELIF条件为TRUE
a = 0
b = 0
c = 0
r = 0
soma = 1
sub = 2
div = 3
mult = 4
print('enter the number corresponding to the operation you want to do:\n')
print('Sum [1]')
print('Subtraction[2]')
print('Divisao [3]')
print('Multiplication [4]')
r = int(1)
while (r == 1):
operacao = 0
operacao = input('\n>')
if operacao == soma:
a = int(input('Enter the value of a:'))
b = int(input('Enter the value of b:'))
c = a + b
print ('\n A Soma de {} mais {} equivale a: {}'.format(a,b,c))
elif operacao == sub:
a = int(input('Enter the value of a:'))
b = int(input('Enter the value of b:'))
c = a - b
print ('\n A subtracao de {} menos {} equivale a: {}'.format(a,b,c))
elif operacao == div:
a = int(input('Enter the value of a:'))
b = int(input('Enter the value of b:'))
c = a / b
print ('\n A divisao de {} de {} equivale a: {}'.format(a,b,c))
elif operacao == mult:
a = int(input('Enter the value of a:'))
b = int(input('Enter the value of b:'))
c = a * b
print ('\n The multiplication of {} by {} is equivalent to: {}'.format(a,b,c))
else: #going direct to here...
print('\n Unrecognized operation')
EXPECTED that the ELIF conditions would work when true,but not working. 预计ELIF条件在真实时会起作用,但不起作用。
input
returns a string
, so you'll need to do operacao = int(input('\\n>'))
, otherwise str == int
will always be False
: input
返回一个string
,所以你需要做operacao = int(input('\\n>'))
,否则str == int
将永远为False
:
x = input("\n>") # I've input 5
x
# '5'
# returns False because x is a string
x == 5
# False
# converts x to int, so returns True
int(x) == 5
# True
# returns True because we are comparing to a string
x == '5'
# True
So for your code: 所以对于你的代码:
# convert the return of input to int for comparing against other ints
operacao = int(input('\n>')) # I'll put 3
if operacao == 1:
print('got one')
elif operacao == 3:
print('got three')
# got three
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