Xml序列化添加具有属性的元素

Question

I have two classes:

public class A
{
    [XmlElement("Content")]
    public B SomeName { get; set; }
}

public class B
{
    [XmlAttribute]
    public int X { get; set; }
}

It serializes into xml like this:

<A>
  <Content X="5" />
</A>

I would like to specify element name in Content and gets something like this

<A>
  <Content>
      <Some element X="5" />
  </Content>
</A>

Can i do this without creating new class witch will contains B using standart xml serialization?

Answer 1

One option you have is to declare the SomeName property in class A as a collection of objects of type B and then make use of the [XmlArray] and [XmlArrayItem] attributes.

Here is a working example. Be aware that I changed the property SomeName to SomeNames .

[Serializable]
public class A
{
    [XmlArray("Content")]
    [XmlArrayItem("Some")]
    public List<B> SomeNames { get; set; } = new List<B>();
}

public class B
{
    [XmlAttribute(AttributeName = "element")]
    public int X { get; set; }
}

public static void XmlSerialize()
{
    var a = new A {SomeNames = new List<B> {new B() {X = 5}}};
    var serializer = new XmlSerializer(typeof(A));
    var settings = new XmlWriterSettings() {Indent = true};
    using var stream = XmlWriter.Create("serialized.xml", settings);
    serializer.Serialize(stream, a);
}

The result produced by this example will be as desired by you:

<?xml version="1.0" encoding="utf-8"?>
<A xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <Content>
    <Some element="5" />
  </Content>
</A>