简体   繁体   English

数组初始化优化

[英]Array initialization optimization

When compiling the following code snippet (clang x86-64 -O3 ) 编译以下代码片段时(clang x86-64 -O3

std::array<int, 5> test()
{
    std::array<int, 5> values {{0, 1, 2, 3, 4}};
    return values;
}

It produced the typical assembly that I would expect 它产生了我期望的典型装配

test():                               # @test()
        mov     rax, rdi
        mov     ecx, dword ptr [rip + .L__const.test().values+16]
        mov     dword ptr [rdi + 16], ecx
        movups  xmm0, xmmword ptr [rip + .L__const.test().values]
        movups  xmmword ptr [rdi], xmm0
        ret
.L__const.test().values:
        .long   0                       # 0x0
        .long   1                       # 0x1
        .long   2                       # 0x2
        .long   3                       # 0x3
        .long   4                       # 0x4

However for small arrays, it seems to have figured out a trick? 然而对于小型阵列,似乎已经找到了一个技巧?

std::array<int, 3> test()
{
    std::array<int, 3> values {{0, 1, 2}};
    return values;
}

This was the corresponding assembly 是相应的装配

test():                               # @test()
        movabs  rax, 4294967296
        mov     edx, 2
        ret

Where did that magic number ( 4294967296 ) come from? 这个神奇的数字( 4294967296 )来自哪里? Is that essentially a value that can be reinterpret_cast back into an array of int somehow? 这本质上是一个值,可以以某种方式reinterpret_cast为一个int数组吗?

A std::array<int, 3> is 96 bits wide on your implementation. std::array<int, 3>在您的实现上是96位宽。 As such the ABI declares that it should be returned in RAX + the low 32 bits of RDX (aka EDX). 因此,ABI声明它应该在RAX + RDX的低32位(也称为EDX)中返回。

4294967296 is 2 32 , in hex it is $1'0000'0000 . 4294967296是2 32 ,十六进制是$1'0000'0000 So the movabs stores 0 in the low order 32 bits of RAX, and 1 in the high order bits of RAX. 因此, movabs在RAX的低位32位存储0,在RAX的高位位存储1。 The mov stores 2 in EDX (which is exactly what you wanted). mov在EDX中存储了2个(这正是你想要的)。

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM