将空命令行传递到源脚本

Question

My bash script expects command line arguments that I parse without any problem. However the script later calls an other script which also accepts positional parameters, but providing parameters is not mandatory.

When my script source s the other script without arguments the other script still tries to parse those arguments that were given to my script in the first place.

I have two solutions, but none of them looks good to me.

1. With shift :

    # now making this script to handle branches: OPTIND=1 while getopts "b:" opt; do case "$opt" in 'b' ) branch=$OPTARG ;; esac shift done 

2. Passing empty argument to the second script:

    source ${MINICONDA}/bin/activate "" 

Answer 1

Note that this isn't needed for normal calls of a script as an external process, but only for invocations with source or . .

To provide context to readers, from bash's built-in help to source :

If any arguments are supplied, they become the positional parameters when filename is executed. Otherwise the positional parameters are unchanged.

---

The easiest way to control the argument list is using set -- arg1 arg2 ... to immediately overwrite it with a new list. Thus:

orig_args=( "$@" )        # back up the original arguments
set --                    # clear the argument list

source whatever

set -- "${orig_args[@]}"  # if you ever need them back