[英]Trouble casting integer object to primitive type
I'm trying to do this challenge on codewars : https://www.codewars.com/kata/554ca54ffa7d91b236000023/train/java I changed the original array into an arraylist, but then I have to use the values in arrayist to do some comparisons with primitive types. 我正在尝试在codewars上进行此挑战: https ://www.codewars.com/kata/554ca54ffa7d91b236000023/train/java我将原始数组更改为arraylist,但是随后我必须使用arrayist中的值来做一些操作与原始类型的比较。
I tried to cast the Integer objects using (int) but there's still casting errors. 我尝试使用(int)强制转换Integer对象,但仍然存在强制错误。 When I tried to do (int)(arrList.get(j)).equals(current), it tells me boolean can't be converted to int.
当我尝试执行(int)(arrList.get(j))。equals(current)时,它告诉我布尔值无法转换为int。
import java.util.*;
public class EnoughIsEnough {
public static int[] deleteNth(int[] elements, int maxOccurrences) {
ArrayList arrList = new ArrayList<>(Arrays.asList(elements));
for (int i = 0; i < arrList.size(); i++) {
int current = (int)arrList.get(i);
int occurrences = 1;
for (int j = i + 1; j < arrList.size(); j++) {
if (arrList.get(j).equals(current) && occurrences >= maxOccurrences) {
arrList.remove(j);
} else if (arrList.get(j).equals(current)) {
occurrences++;
}
}
}
int arr[] = new int[arrList.size()];
for (int i = 0; i < arrList.size(); i++) {
arr[i] = (int) arrList.get(i);
}
return arr;
}
}
It compiled but the test shows : class [I cannot be cast to class java.lang.Integer ([I and java.lang.Integer are in module java.base of loader 'bootstrap') 它已编译,但测试显示:类[无法将其强制转换为类java.lang.Integer([和java.lang.Integer在加载程序'bootstrap'的模块java.base中)
Arrays.asList(elements)
does not do what you think it does, it returns a list of containing the int[] array, not the elements of the array. Arrays.asList(elements)
并没有您认为的那样,它返回一个包含int []数组而不是数组元素的列表。 You can not create a list of primitives. 您无法创建基元列表。 If you want to use List you must first convert the
int
to Integer
. 如果要使用List,则必须首先将
int
转换为Integer
。
You can get a List of Integer
with 您可以使用获取
Integer
列表
List<Integer> arrList = Arrays.stream(elements).boxed().collect(Collectors.toList());
however, you still have a bug in your program where you will skip numbers. 但是,您的程序中仍然存在一个错误,您将跳过数字。
for (int j = i + 1; j < arrList.size(); j++) {
if (arrList.get(j).equals(current) && occurrences >= maxOccurrences) {
arrList.remove(j); // This shortens the list causing us to skip the next element
j--; // One hackish way is to go back one step
} else if (arrList.get(j).equals(current)) {
occurrences++;
}
}
One solution is to loop backwards instead 一种解决方案是改为向后循环
for (int j = arrList.size() - 1; j > i; j--) {
if (arrList.get(j).equals(current) && occurrences >= maxOccurrences) {
arrList.remove(j);
} else if (arrList.get(j).equals(current)) {
occurrences++;
}
}
You can replace 您可以更换
ArrayList arrList = new ArrayList<>(Arrays.asList(elements));
with 同
List<Integer> arrList = Arrays.stream(elements).boxed().collect(Collectors.toList());
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