如何比较两个具有不同长度的列表并删除一些元素？

Question

I have two lists, the first contains some elements that don't exist in the second list which have more elements. I need to delete elements that don't exist in the second list.

In the example below, I need to delete just the '0' from the first list. So:

Input:
list1 = [0,1,2,3]
list2 = [1,2,3,4,5,6,7]

Output:
list1 = [1,2,3]
list2 = [1,2,3,4,5,6,7]

I tried this simple code but it return an empty list

list1=[0,1,2,3]
list2=[1,2,3,4,5,6,7]

for element in list1:
    for element1 in list2:
        if element != element1:
            for element in list1:
                list1.remove(element)
print(list1)

Any help please ?

Answer 1

You can use sets to do this!

set(list1).intersection(list2) # [1,2,3]

You can also use list comprehension but it's slower in theory.

list1 = [0,1,2,3]
list2 = [1,2,3,4,5,6,7]

list1 = [x for x in list1 if x in list2] # [1,2,3]