我有不同的zip文件，每个文件包含一个csv文件。 如何解压缩每个文件夹，并将所有csv文件保存在一个文件夹中

Question

The codes I have written, for some reasons does not work.

import pandas as pd
import glob
import zipfile

path = r"C:/Users/nano/Documents/Project" # use your path
all_files = glob.glob(path + "/*.gz")

for folder in all_files:
    with zipfile.ZipFile(folder,"r") as zip_ref:
        zip_ref.extractall(path)

Answer 1

First you are using Zip against Gzip. So you need to use the right library. Below is a working example of the code.

import glob
import os
import gzip

path = r"C:/Temp/Unzip" # use your path
all_files = glob.glob(path + "/*.gz")
print(all_files)
for file in all_files:
    path, filename = os.path.split(file)
    filename = os.path.splitext(filename)[0]
    with gzip.open(file,"rb") as gz:
        with open('{0}/{1}.csv'.format(path, filename), 'wb') as cv:
            cv.writelines(gz.read())

Answer 2

gzip (.gz) and zip (.zip) are two different things. For gzip, you can use gzip :

import glob
import gzip
import shutil

path = r"C:/Users/shedez/Documents/Project" # use your path
all_files = glob.glob(path + "/*.gz")

for folder in all_files:
     dst=folder[:-3] # destination file name
     with gzip.open(folder, 'rb') as f_in, open(dst, 'wb') as f_out:
         shutil.copyfileobj(f_in, f_out)

Answer 3

If you use gz (gZip) format, you might want to look at the gzip package, I'm not aware of an extract method, but you can do something as such, using pandas purely, which i find more convenient:

for folder in all_files:
    c = pd.read_csv(folder, compression='gzip')
    c.to_csv(path+folder[:-2]+"csv")

the [:-2] is to cut the "gz", and you might want to either change the parameters of read_csv (adding header row, or whatever) or the flags of to_csv (setting the arguments header=False, index_label=False to prevent panda adding you undesired stuff

alternatively, you could open it with gzip

import gzip
import shutil
with open(folder, 'rb') as f_in, gzip.open(folder[:-2]+"csv", 'wb') as f_out:
    shutil.copyfileobj(f_in, f_out)

Answer 4

Try out this code:

import os, zipfile

dir_name = 'C:\\Users\\shedez\\Documents\\Project' # ZIP location
extract_dir_name = 'C:\\Users\\shedez\\Documents\\Project\\Unziped' # CSV location after unzip
extension = ".zip" # you might have to change this

os.chdir(dir_name) # change directory from working dir to dir with files

for item in os.listdir(dir_name): # loop through items in dir
    if item.endswith(extension): # check for ".zip" extension
        file_name = os.path.abspath(item) # get full path of files
        zip_ref = zipfile.ZipFile(file_name) # create zipfile object
        zip_ref.extractall(extract_dir_name) # extract file to dir
        zip_ref.close() # close file

If you want to learn more about zipFile , click here .