使用Java正则表达式获取文本文件每一行的特定部分

Question

I have a text file that is multiple of lines of "(what I want to grab)" , "junk" , "junk" , "junk" separated by newlines. I'm reading the file into a list of strings and trying to use regex to print out what I want to grab, but I cannot seem to get this to work.

The way I understand regex, ^ matches the start of a new line, \\" matches to the first quotation after ^ , . matches anything, then \\" matches the next quotation. What am I missing?

List<String> result = Files.readAllLines(Paths.get("file.txt"));

Pattern pattern = Pattern.compile("^\".\"");

for (int i = 0; i < result.size(); i++)
{
    System.out.println(result.get(i));
    Matcher matcher = pattern.matcher(result.get(i));
    System.out.println(matcher.find());
}

Answer 1

Here's a simple regex which should solve your problem:

String regex = "(^[\"][^\"]+[\"])";

This will match the beginning of the line, then directly afterwards it will match one single quotation mark. Then it'll match anything except a quotation mark until it reaches one.

Another (possibly more legible) version from Aaron in the comments.

^\"[^\"]+\"

Choose which you prefer.

Tested here .