从 php 回显时 Javascript 未运行

Question

I am trying to print some code from PHP after clicking button in JavaScript, however the code is not running and I can't see any errors.

<script type="text/javascript  src="https://code.jquery.com/jquery- 
3.4.1.min.js" > 
$( document ).ready(function() {
<?php echo '$("button[data-id='. $transport[0]['request']['vehicleType'] 
. ']" ).click();'; ?>
});
</script>

...

<script type="text/JavaScript  src=" https:="" code.jquery.com="" jquery 
3.4.1.min.js"=""> 
$( document ).ready(function() {
$("button[data-id=seated]" ).click();});
</script>

Running the code in console works just fine and the button is clicked,however echoing from php the code is present without errors but not executed and the button is not clicked.

Answer 1

the code is not working even like this

php

<script src="https://code.jquery.com/jquery-3.4.1.min.js" >  </script>
<script type="text/javascript"> 
 $( document ).ready(function() {
  <?php echo '$("button[data-id='. $transport[0]['request']['vehicleType'] . ']" ).click();'; ?>
});
 </script>

js output

<script src="https://code.jquery.com/jquery-3.4.1.min.js">  </script>
<script type="text/javascript"> 
 $( document ).ready(function() {
  $("button[data-id=seated]" ).click();});
 </script>

those missing quotes and slashes came from formatting my question, im new to the forum so i wasn't sure how to format the code.

Answer 2

<script src="https://code.jquery.com/jquery-3.4.1.min.js" >  </script>
<script type="text/javascript"> 

 $( document ).ready(function() {
   setTimeout(function(){ <?php echo '$("button[data-id='. $transport[0]['request']['vehicleType'] . ']" )[0].click()' ?> }, 100)
  setTimeout(function(){  <?php echo '$("input[value='.  $transport[0]['request']['vehicleSpecification'] . ']")[0].click();'; ?> }, 100)
});
 </script>

A small time out and ref to element 0 was enough to make it work