如何显示第一个表中的记录并匹配第二个表中的记录？

Question

I have two tables, One is for student details and second is for stud_marks.

I am inserting the personal information in student table like

  s_id  | name   | mobile     | email  
    1   | asdff  |1234567831  |asd@gmail.com
    2   | kjhgg  |1231231231  |mnhg@gmail.com
    <!--many more-->

and I am inserting the student marks like

m_id    |sub_name    |mark       | stu_id    |date_of_added
1       |asdasd      |30         | 1       |2019-06-16 17:31:07
2       |oiuytr      |40         | 1       |2019-06-16 17:31:07
3       |okjhyt      |50         | 2       |2019-06-20 20:12:09
4       |ppoiuj      |60         | 1       |2019-06-22 11:41:34
<!--many more--> 

Now, what query I have to use and display the single records. Like I have to display the student 1 record. so My expected output is

 s_id  | name   | mobile     | email  
   1   | asdff  |1234567831  |asd@gmail.com


m_id    |sub_name    |mark       | stu_id    |date_of_added
1       |asdasd      |30         | 1       |2019-06-16 17:31:07
2       |oiuytr      |40         | 1       |2019-06-16 17:31:07
4       |ppoiuj      |60         | 1       |2019-06-22 11:41:34

I am on the edit page and there I have to display the records like

name:-asdff
mobile:-1234567831
Email:-asd@gmail.com

<!--subject details-->
Sub_name Mark
asdasd   30         
oiuytr   40
ppoiuj   60      

I can display the records on the HTML page. Personal information is display. I can use for each for displaying the subject details.

I am using CodeIgniter.

I tried below query but I am getting 3 records.

SELECT * FROM `student` LEFT JOIN stud_marks ON student.s_id=stud_marks.stu_id WHERE student.s_id=1

the output of the query is

1 asdff 1234567831 asd@gmail.com 1 asdasd 30 1 2019-06-16 17:31:07

1 asdff 1234567831 asd@gmail.com 2 asdasd 40 1 2019-06-16 17:31:07

1 asdff 1234567831 asd@gmail.com 4 asdasd 60 1 2019-06-22 11:41:34

Would you help me out with this issue?

Answer 1

Try this :

//assuming your database connection will be in $con
$sql="SELECT * FROM `student` LEFT JOIN stud_marks ON   student.s_id=stud_marks.stu_id WHERE student.s_id=1";
 $result=mysqli_query($con,$sql);
 while($row = $result->fetch_assoc()){
 $name=$row['name'];
 $mobile=$row['mobile'];
 $email=$row['email'];
 $marks[]=$row['mark'];
 $sub_names[]=$row['sub_name'];
 }
 $records=count($sub_names);
 echo 'Name :'.$name; echo '<br>';
 echo 'Mobile :'.$mobile; echo '<br>';
 echo 'Email :'.$email; echo '<br>';
 echo '------'; echo '<br>';
 echo 'Subject    Marks'; echo '<br>';
 for ($x = 0; $x <= $records; $x++) {
 echo "$sub_names[$x]  $marks[$x]   <br>";
 }
 echo '------'; echo '<br>';

CodeIgniter example to extract data:

$query = $this->db->query("YOUR QUERY");

foreach ($query->result_array() as $row)
{
        $name=$row['name'];
        $mobile=$row['mobile'];
        $email=$row['email'];
        $marks[]=$row['marks'];
        $sub_names[]=$row['sub_names'];
}

For displaying the result, no change in code starting from $records=count($sub_names) in my previous example.