在bash脚本中循环执行命令时，如何从cURL将响应正文保存到文件中？

Question

I've created a cURL bash script in which I want to save the response body into a file called output.log , but when I open the file output.log it looks like this:

Here is my bash script:

#!/bin/bash
SECRET_KEY='helloWorld'
FILE_NAME='sma.txt'

function save_log()
{

    printf '%s\n' \
    "Header Code    : $1" \
    "Executed at    : $(date)" \
    "Response Body  : $2" \
    '==========================================================\n'  > output.log
}

while IFS= read -r line; 
    do 
        HTTP_RESPONSE=$(curl -I -L -s -w "HTTPSTATUS:%{http_code}\\n" -H "X-Gitlab-Event: Push Hook" -H 'X-Gitlab-Token: '$SECRET_KEY --insecure $line 2>&1)
        HTTP_STATUS=$(echo $HTTP_RESPONSE | tr -d '\n' | sed -e 's/.*HTTPSTATUS://')

        save_log $HTTP_STATUS $HTTP_RESPONSE
done < $FILE_NAME

Can anyone help me get my desired output in my output.log?

Answer 1

从Curl文档中：-I，--head仅显示文档信息删除-I或将其替换为-i应该可以解决您的问题