递归排除node_modules

Question

I came across a specific issue when setting up Firebase in my project directory.

Initially, project's hierarchy could be summed up by the following :

.
./src
./src/my_code.js
./src/my_code.test.js
./node_modules
./node_modules/...
./package.json

To run my tests, I'm using mocha.

On this very website, I found a really useful regexp able to match all *.test.js files in the whole project hierarchy, except the node_modules "branch" :

./{,!(node_modules)/**}/*test.js

Next step for me was to initialize Firebase Functions & Hosting in the directory.

A design choice was made to set up the functions folder in ./src .

After running firebase init and answering all the questions, my folder looked like that :

.
./src
./src/my_code.js
./src/my_code.test.js
// ===== NEW =====
./src/functions
./src/functions/index.js
./src/functions/index.test.js
./src/functions/node_modules
./src/functions/node_modules/...
./src/functions/package.json
// ===============
./node_modules
.node_modules/...
./package.json

The problem lies in that the regexp appears not to exclude the ./src/functions/node_modules folder .

I'm not really at ease to extend this cool regexp, not knowing if I have to add ** or a !(src/functions/node_modules) somewhere.

Answer 1

I took a deep look into this mochajs' issue .

First of all, it appears that, as @Wiktor mentioned in my question's comments, ./{,!(node_modules)/**}/*test.js isn't a regex, but a glob.

I didn't investigated this concept further for now, because mochajs now implement an --exclude flag feature.

My solution is the following : mocha \\"./**/*test.js\\" --exclude \\"./**/node_modules/**\\" .