如何使用sed命令删除短语后的数字和日期时间？

Question

Following syntax delete everything after specific phrase:

s/\(.*\Build ID:.\).*/\1/g
s/\(.*\Build Date:.\).*/\1/g

However I need to secure this part of code and to delete:

• only 8 digits number date time after specific phrase
• only date time (YYYY-MM-DD space HH:MM:SS) after specific phrase

Input:

Build ID: 14257823
Build Date: 2019-06-27 03:09:33

Output:

Build ID:
Build Date:

To cut only 8-digits and time stamp please use:

s/[0-9]\\{8\\}//gs/[0-9]\\{4\\}\\-[0-9]\\{2\\}\\-[0-9]\\{2\\} [0-9]\\{2\\}:[0-9]\\{2\\}:[0-9]\\{2\\}//g

Answer 1

You can use character classes and repetition quantifier.

The build id format in your example is [0-9]\\{8\\} (the character class takes all digits and repeats them 8 times) and the date format is [0-9]\\{4\\}\\-[0-9]\\{2\\}\\-[0-9]\\{2\\} [0-9]\\{2\\}:[0-9]\\{2\\}:[0-9]\\{2\\} :

• four digits
• hyphen
• two digits
• hyphen
• two digits
• space
• two digits
• colon
• two digits
• colon
• two digits

This gives the following regexes

s/\(.*Build ID:.\)[0-9]\{8\}/\1/g
s/\(.*Build Date:.\)[0-9]\{4\}\-[0-9]\{2\}\-[0-9]\{2\} [0-9]\{2\}:[0-9]\{2\}:[0-9]\{2\}/\1/g