如何使用CodeIgniter插入多个动态数据？

Question

I am using CodeIgniter, I am displaying the fields dynamically. Now I have to insert the data in the database. So I tried below code.

$order = $this->input->post('order[]');
$partner = $this->input->post('parner[]');
$bankname = $this->input->post('newpartner[]');
$status = $this->input->post('filestatus[]');
$user_id = $this->input->post('user_id');

$order_length = sizeof($order);

for ($j = 0; $j < $order_length; $j++) {

  if (($status = 1) || ($status = 3)) {
    $remark = $this->input->post('remark[]');
  } else {
    $remark = "";
  }

  if (($status = 2) || ($status = 4))) {
  $reasonDate = $this->input-> post('reasonDate[]');
  $remark = $this->input-> post('remark[]');
} else {
  $reasonDate = "";
  $remark = "";

}

if ($status = 7) {
  $reasonAmt = $this->input->post('reasonAmt[]');
  $reason = $this->input->post('reason[]');
} else {
  $reasonAmt = "";
  $reason = "";
}


$data['row'] = array(
  'order' => $order[$j],
  'bankname' => $bankname[$j],
  'status' => $status[$j],
  'lead_id' => $user_id,
  'remark' => $remark[$j],
  'reasonDate' => $reasonDate[$j],
  'reasonAmt' => $reasonAmt[$j],
  'reason' => $reason[$j]
);
$save = array(
  'b_orderno' => $data['row']['order'],
  'b_bankname' => $data['row']['bankname'],
  'b_filestatus' => $data['row']['status'],
  'p_id' => $data['row']['pid'],
  'lead_id' => $data['row']['lead_id'],
  'b_remark' => $data['row']['remark'],
  'b_date' => $data['row']['reasonDate'],
  'b_amt' => $data['row']['reasonAmt'],
  'b_reason' => $data['row']['reason']
);

$afterxss = $this->security-> xss_clean($save);
if ($afterxss) {
  $this - > db - > insert('tbl_bankdata', $afterxss);
  $response['error'] = "true";
  $response['msg'] = "added successfully";

} else {
  $response['error'] = "false";
  $response['msg'] = "Sometning wrong! please check the internet connection and try again";
}

}
echo json_encode($response);

I am getting the issue on the status field because depending upon the status value input field will display. Also, I used If the condition in logic for the status field. Each row has a unique status field.

You will find my HTML and script in below link.

https://jsfiddle.net/08phzue3/

This is my UI screenshot. Ignore the value that is only for testing purpose.

1)Onload this will display 2) If user select the status 3) If multiple row

Would you help me out with this?

Answer 1

Actually you are not comparing here:

if (($status = 1) || ($status = 3)) {

You are assigning the values to your $status variable

this should be:

if (($status == 1) || ($status == 3)) {

Side note: same for other conditions as well.

Edit:

As you mentioned you are getting array in $status so using comparison is not a correct logic here, there are multiple solution available,

You can use in_array() like:

if(in_array(1, $status) || in_array(3, $status)){
    $remark = $this->input->post('remark[]');   
}
else{
    $remark = "";   
}

Final Solutions (04-07-2019):

After changing the $save and $data arrays, issue has been resolved for OP:

$save['b_orderno'] = $order[$j]; 
$save['b_bankname'] = $bankname[$j]; 
$save['b_filestatus'] = $status[$j]; 
$save['p_id'] = $partner[$j]; 
$save['lead_id'] = $user_id; 


if(!empty($remark[$j])){ 
$save['b_remark'] = $remark[$j]; 
} 
if(!empty($reasonDate[$j])){ 
$save['b_date'] = $reasonDate[$j]; 
} 
if(!empty($message[$j])){ 
$save['b_message'] = $message[$j]; 
} 
if(!empty($reasonAmt[$j])){ 
$save['b_amt'] = $reasonAmt[$j]; 
} 
if(!empty($reason[$j])){ 
$save['b_reason'] = $reason[$j]; 
}


$data['row']['order'] = $order[$j]; 
$data['row']['bankname'] = $bankname[$j]; 
$data['row']['status'] = $status[$j]; 
$data['row']['lead_id'] = $user_id; 
$data['row']['remark'] = $remark[$j]; 
$data['row']['reasonDate'] = $reasonDate[$j]; 

if(!empty($reasonAmt[$j])){ 
$data['row']['reasonAmt'] = $reasonAmt[$j]; 
} 
if(!empty($reason[$j])){ 
$data['row']['reason'] = $reason[$j]; 
}