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无法在GitLab CI中生成签名的APK

[英]Can't generate signed APK in GitLab CI

I'm testing gitlab ci/cd and I'm trying to build a signed APK but my script failed. 我正在测试gitlab ci / cd,并尝试构建一个已签名的APK,但是我的脚本失败了。 What should I change or add? 我应该更改或添加什么?

I add variables KEYSTORE_FILE, KEYSTORE_PASSWORD, KEY_ALIAS, KEY_PASSWORD with values. 我将变量KEYSTORE_FILE,KEYSTORE_PASSWORD,KEY_ALIAS,KEY_PASSWORD与值相加。

assembleRelease:
 stage: release
 script:
 - echo $KEYSTORE_FILE | base64 -d > my.keystore
 - ./gradlew assembleRelease
 -Pandroid.injected.signing.store.file=$(pwd)/my.keystore
 -Pandroid.injected.signing.store.password=$KEYSTORE_PASSWORD
 -Pandroid.injected.signing.key.alias=$KEY_ALIAS
 -Pandroid.injected.signing.key.password=$KEY_PASSWORD
  artifacts:
  paths:
  - app/build/outputs/apk/release

Error: 错误:

FAILURE: Build failed with an exception.
What went wrong:
Execution failed for task ':app:packageRelease'.
1 exception was raised by workers:
java.lang.RuntimeException: 
com.android.ide.common.signing.KeytoolException: Failed to read key  from 
store "/builds/juantamad.02072019/2019_samplebuild/my.keystore": null

But it should be successfully 但这应该成功

Provided you have correct indentations (as posted they are not), the problem is likely to be caused by multi-line command - it just executes - ./gradlew assembleRelease first, without further arguments 如果您有正确的缩进( - ./gradlew assembleRelease ),则该问题很可能是由多行命令引起的-它只是执行- ./gradlew assembleRelease首先,没有其他参数

To wrap the long line you can use YAML multi-line strings: 要包装长行,可以使用YAML多行字符串:

  script:
   - ...
   - >
     ./gradlew assembleRelease
       -Pandroid.injected.signing.store.file=$(pwd)/my.keystore
       -Pandroid.injected.signing.store.password=$KEYSTORE_PASSWORD
       -Pandroid.injected.signing.key.alias=$KEY_ALIAS
       -Pandroid.injected.signing.key.password=$KEY_PASSWORD

Read more: 阅读更多:

-- -

Another possible cause - if your env var is set as Protected in project settings, 另一个可能的原因-如果您的环境变量在项目设置中设置为“ 受保护”
and you are working in a branch which is not Protected . 并且您正在不受保护的分支中工作。
Then var is not passed to your job 然后var不会传递给您的工作

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