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如何解决代码中的“无效的内存引用”错误?

[英]How can I fix the “Invalid memory reference” error in my code?

I'm working on a maze-solver robot for my arduino project. 我正在为arduino项目开发迷宫求解器机器人。 I want my robot to memorize the maze and then find the shortest path. 我希望我的机器人记住迷宫,然后找到最短的路径。 I keep having a problem when the char array's lenght is 3. 当char数组的长度为3时,我一直遇到问题。

The problem appears when the lenght is <= 3, so I tried diffrent stuff to make a particular case out of that, that's why the if (strlen(a) > 3) is there. 当长度小于等于3时出现问题,因此我尝试了不同的方法来制作一个特殊的案例,这就是为什么if (strlen(a) > 3)在那的原因。

#include <iostream>
#include <string.h>
#include <stdio.h>

using namespace std;

int main()
{
    char a[] = "LLLBLLLRBLLBSRSRS";
    char b[200];

    while(strcmp(a, b) != 0) {
        strcpy(b, a); //sa verific daca se schimba sirul, daca nu inseamna ca a ajuns la minim
    for(int i = 0; i < strlen(a) - 2; i++)
    {
        if(a[i] == 'L' && a[i + 1] == 'B' && a[i + 2] == 'R') //if urile astea cauta combinatii de cate 3 miscari sa optimizezi drumul
        {
            a[i] = 'B';
            if (strlen(a) > 3) strcpy(a + i + 1, a + i + 3);
            else a[i + 1] = '\0';
        }

        else if(a[i] == 'L' && a[i + 1] == 'B' && a[i + 2] == 'S')
        {
             a[i] = 'R';
            if (strlen(a) > 3) strcpy(a + i + 1, a + i + 3);
             else a[i + 1] = '\0';

        }

        else if(a[i] == 'L' && a[i + 1] == 'B' && a[i + 2] == 'L')
        {
             a[i] = 'S';
            if (strlen(a) > 3) strcpy(a + i + 1, a + i + 3);
            else a[i + 1] = '\0';
        }

        else if(a[i] == 'S' && a[i + 1] == 'B' && a[i + 2] == 'L')
        {
             a[i] = 'R';
            if (strlen(a) > 3) strcpy(a + i + 1, a + i + 3);
            else a[i + 1] = '\0';
        }

        else if(a[i] == 'S' && a[i + 1] == 'B' && a[i + 2] == 'S')
        {
             a[i] = 'B';
            if (strlen(a) > 3) strcpy(a + i + 1, a + i + 3);
            else a[i + 1] = '\0';
        }

        else if(a[i] == 'R' && a[i + 1] == 'B' && a[i + 2] == 'L')
        {
             a[i] = 'B';
            if (strlen(a) > 3) strcpy(a + i + 1, a + i + 3);
            else a[i + 1] = '\0';
        }
    }
     cout << a << endl;
    }


    return 0;
}

This is the output: 这是输出:

LLSLLBRRSRS LLSLBRSRS LLSBSRS LLBRS LBS LLSLLBRRSRS LLSLBRSRS LLSBSRS LLBRS LBS

and then the error message Runtime error(Exit status:139(Invalid memory reference)). 然后出现错误消息运行时错误(退出状态:139(无效的内存引用))。

The goal is to make the last output be R, because LBS means R. Thanks for the attention! 目标是使最后一个输出为R,因为LBS表示R。感谢您的关注!

The reason for invalid memory reference is in the loop consition: 无效的内存引用的原因在于循环条件:

for(int i = 0; i < strlen(a) - 2; i++)

you are accessing a[i + 2] inside loop so the last iteration must end at i < strlen(a) - 3 : 您正在循环中访问a[i + 2] ,因此最后一次迭代必须在i < strlen(a) - 3

for(int i = 0; i < strlen(a) - 3; i++)

this just fixes your memory problem. 这只是解决您的内存问题。 you still get LBS as the last output. 您仍然会得到 LBS作为最后的输出。

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