在具有1个猫鼬查询的函数中使用async await很好吗？

Question

I am just confused if it's good to use async await in such cases:

import User from models/User

export const getUser = async (_id) => {
  const user = await User.findOne({ _id })
  if (user) return user 
  return null 
}

export const getUser = async (_id) => {
   return await User.findOne({ _id })
}

Since mongoose return promise but I am just confused since with async, but here, it's only 1 query on db? unlike this:

export const getUser = async (_id) => {
   try { 
     const user = await User.findOne({ _id })
     const comments = await User.findOne({ _id })
     return { user, comments }
   } catch(e) {
     console.log('something went wrong', e)
     return null
   }
}

since it's 2 query then you have to await the 1st one then the 2nd, but when you have to await only 1 query, does it resolve?

Answer 1

async functions will always return Promises, so there's really no need for async/await in the case of a single find(). Might as well do this:

export const getUser = (_id) => {
   return User.findOne({ _id })
}

...

getUser(aUserId).then(user => console.log(user))