如何将python脚本的输出存储在变量中

Question

I have a python script 'script1.py' which creates a dictionary 'out_dict' at the end of the execution. I'm calling 'script1.py' from another script 'script2.py'.

Is there any way to get only the final dictionary 'out_dict' (note : I have some print statements too in 'scirpt1.py') into a variable in 'script2.py'.

script1.py

......
......
some print statement
......
some print statement
......
out_dict = {...}
print(out_dict)

script2.py

import os
val = os.system("python3.6 script1.py")

Answer 1

At the start of script1.py add

import pickle as p

and after your dict was created add

with open('dict.p', 'wb') ad f:
    p.dump(out_dict, f)

Then in script2.py again import pickle but this time load from a file

import os
import pickle as p
val = os.system("python3.6 script1.py")

with open('dict.p', 'rb') as f:
    your_dict = p.load(f)     # your dict will loaded

OR

You can not save your dict into a file at all and just access it from script1.py like a class var, but you will have to import your first script though.

script2.py example:

import script1

your_dict = script1.out_dict     # your dict var from the first script
print (out_dict)

Answer 2

You need to declare 2 files. The first will contain the function you want to call. Like this:

func.py

def myFunc():
    return 2

In the script you want to call the function you have to do this:

main_script.py

import func

val = func.myFunc()
print(val)

Answer 3

Two ways of doing this:

1. Store the output dictionary in another file which is then read by script2.py
2. As Daniel suggested, use a marker. It would remove the burden of another file but you would need an appropriate marker.

Answer 4

Easier method would be to import one file in another and use that dictionary :

func.py

def function():
    out_file=dict()
    # Your Code
    return out_file

main.py

import func
val = func.function()