当用户单击外部来源的链接时，如何在应用程序中打开特定页面？
[英]How can I open a specific page in my app when the user clicks a link from an outside source?
问题描述
I'm trying to implement a password recovery feature for my mobile app (built with Xamarin.Forms ). 
我正在尝试为我的移动应用程序（使用Xamarin.Forms ）实现密码恢复功能。
The app will have a backend API in Azure, but so far I'm testing in localhost. 该应用程序将在Azure中具有后端API，但到目前为止，我正在localhost中进行测试。
The idea is to make available an option to reset the user password by sending a request to the API (checking if the email exists in the database) and sending an email with a specific URL registered in the app. 想法是通过向API发送请求（检查电子邮件是否存在于数据库中）并发送带有在应用程序中注册的特定URL的电子邮件，来提供一个重置用户密码的选项。
I understand what I have to do in the backend, it's the app link to open a page in app that I'm interested in (Android and iOS). 我了解我在后端必须执行的操作，它是在我感兴趣的应用（Android和iOS）中打开页面的应用链接。
Is there anyway of doing this? 反正有这样做吗？
1 个解决方案
解决方案1
0 2019-07-05 13:47:55
Yes you can. 是的你可以。 I won't copy all the configurations, but here is a complete tutorial on how to achieve that. 我不会复制所有配置，但是这里是有关如何实现该配置的完整教程 。
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