[英]Formatting API JSON response using PHP
I have an api and i want to parse data from it using php我有一个 api,我想使用 php 解析它的数据
That's the response这就是回应
{
"success": true,
"data": [
{
"medicineId": 12,
"medicineName": "Abacavir"
},
{
"medicineId": 10,
"medicineName": "Alclometasone"
},
{
"medicineId": 15,
"medicineName": " Alectinib"
},
{
],
"message": "Successfully retrieved"
}
I want to list all medicine names我想列出所有药物名称
i tried this but it doesn't get the name just the success response我试过这个,但它没有得到名字只是成功的反应
$age = file_get_contents('link');
$array = json_decode($age, true);
foreach($array as $key=>$value)
{
echo $key . "=>" . $value . "<br>";
}
You can easily list all medicine names with their id like this way by looping $array['data']
array.通过循环$array['data']
数组,您可以像这样轻松地列出所有带有 id 的药物名称。 Let's do this way-让我们这样做-
<?php
$age = '{"success":true,"data":[{"medicineId":12,"medicineName":"Abacavir"},{"medicineId":10,"medicineName":"Alclometasone"},{"medicineId":15,"medicineName":" Alectinib"}],"message":"Successfully retrieved"}';
$array = json_decode($age, true);
$medicine_names = [];
foreach($array['data'] as $key=>$value)
{
$medicine_names[$value['medicineId']] = $value['medicineName'];
}
print_r($medicine_names);
echo implode(' ', $medicine_names);
?>
Output:输出:
Array (
[12] => Abacavir
[10] => Alclometasone
[15] => Alectinib
)
WORKING DEMO: https://3v4l.org/tBtaW工作演示: https : //3v4l.org/tBtaW
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