[英]Mysql join - check for non existant rows having certain column values
I have a restaurants
table and a bookings
table. 我有一个restaurants
表和一个bookings
表。 Each booking stores a date, number of persons, and one of 3 time slots ( event_time
). 每个预订都存储日期,人数和3个时隙之一( event_time
)。 An example row: 示例行:
id | restaurant_id | date | number_of_persons | event_time
7 2 2019-09-12 00:00:00 15 2
I want to return all restaurants that has free seats bookable for any event_time on a certain date. 我想退回所有可以预订特定日期任意event_time的免费座位的餐厅。
Restaurants with no bookings are returned using left
join. 没有预订的餐厅使用left
联接返回。 I can get bookings with the join and do SUM(number_of_persons)
and check if max capacity has been met for each event_time that has bookings. 我可以通过加入进行预订,并进行SUM(number_of_persons)
并检查是否已满足每个具有预订的event_time的最大容量。 The problem is that any event_time having 0 bookings is not included in the result (since it is non existant), so it doesn't count. 问题在于结果中不包含任何具有0个预订的event_time(因为它不存在),因此不计算在内。
The current query excludes restaurants which are fully booked for the event_times which has bookings. 当前查询不包括已预订的event_times预订满的餐厅。 So if event_time
1 and 2 are fully booked, and event_time
3 is free and bookable, that restaurant is still excluded (wrongly). 因此,如果event_time
1和2已被预订event_time
,而event_time
3是免费且可预订的,则该餐厅仍将被排除(错误地)。
Here is the current query: 这是当前查询:
select restaurants.id, `restaurants`.title,
number_of_seats_max,
num_persons_booked,
number_of_seats_max - num_persons_booked AS free_seats_left,
event_time
from `restaurants`
left join ( select `restaurant_id`, `b`.`event_time`,
SUM(b.number_of_persons) as num_persons_booked
from `bookings` as `b`
where `event_date` = "2019-9-12"
group by `b`.`event_time`, `restaurant_id`
order by num_persons_booked
) as `bookings_summaries`
on `restaurants`.`id` = `bookings_summaries`.`restaurant_id`
having number_of_seats_max - num_persons_booked > 0 // <-- not fully booked
or num_persons_booked IS NULL //<-- no bookings
I have a fiddle here. 我在这里摆弄 。
The logic I think is needed is: Return restaurants which have bookings and: 我认为需要的逻辑是:退回有预订的餐厅,并且:
or 要么
But I don't know how to implement it. 但是我不知道如何实现它。 I appreciate any help! 感谢您的帮助!
You need to assign event_time 1,2,3 for every place before left join with booking_summerise then only it gives results for every event. 您需要为每个位置分配event_time 1,2,3,然后再与booking_summerise左连接,然后才为每个事件提供结果。
select restaurants.id, `restaurants`.title,
number_of_seats_max,
restaurants.event_time,
IFNULL(num_persons_booked,0) AS num_persons_booked,
number_of_seats_max - IFNULL(num_persons_booked,0) AS free_seats_left
from ((select *,("1") AS event_time from restaurants) UNION ALL (select *,("2") AS event_time from restaurants) UNION ALL (select *,("3") AS event_time from restaurants)) AS restaurants
left join ( select `restaurant_id`, `b`.`event_time`, SUM(b.number_of_persons) as num_persons_booked
from `bookings` as `b`
where `event_date` = "2019-9-12"
group by `b`.`event_time`, `restaurant_id`
order by num_persons_booked
) as `bookings_summaries`
on `restaurants`.`id` = `bookings_summaries`.`restaurant_id` AND
`restaurants`.`event_time` = `bookings_summaries`.`event_time`
having number_of_seats_max - num_persons_booked > 0
or num_persons_booked IS NULL
ORDER BY `restaurants`.`id`
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