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解码base64并将其编码为十六进制

[英]Decode base64 and encode it to hex

I have following code which decodes base64 and then encodes it to hex. 我有以下代码,该代码解码base64,然后将其编码为十六进制。

doc_id := "Can35qPeFkm9Xgmp9+aj3g=="
base64_decode, err := base64.StdEncoding.DecodeString(doc_id)
if err != nil {
log.Fatal("error:", err)
}
base64_decoded := fmt.Sprintf("%q", base64_decode)
fmt.Printf("base_decoded %v\n", base64_decoded)



src := []byte(base64_decoded)
fmt.Println(src)
hex_encode := make([]byte, hex.EncodedLen(len(src)))
hex.Encode(hex_encode, src)
hex_encoded := fmt.Sprintf("%s", hex_encode)
fmt.Printf("hex_encoded %v", hex_encoded)

where doc_id is base64 format. 其中doc_id是base64格式。 base64_decoded is its decoded value. base64_decoded是其解码值。 I have to encode it to hex, so i pass it to src. 我必须将其编码为十六进制,所以我将其传递给src。

The problem is when i pass the identifier base64_decoded to src i get wrong when i pass in the value that base64_decoded is holding i get correct answer. 问题是当我将base64_decoded标识符传递给src时,当我传递base64_decoded持有的值时,我得到了错误的答案。 for example: if i get base64_decoded value as "\\x11z\\xc0[d~\\xfcK\\xb1\\xf8\\x11z\\xc0[d~" if i pass its value which is "\\x11z\\xc0[d~\\xfcK\\xb1\\xf8\\x11z\\xc0[d~", i get correct answer 117ac05b647efc4bb1f8117ac05b647e 例如:如果我将base64_decoded值设置为“ \\ x11z \\ xc0 [d〜\\ xfcK \\ xb1 \\ xf8 \\ x11z \\ xc0 [d〜””,如果我通过了它的值即“ \\ x11z \\ xc0 [d〜\\ xfcK \\ xb1 \\ xf8 \\ x11z \\ xc0 [d〜“,我得到正确的答案117ac05b647efc4bb1f8117ac05b647e

if i pass the variable holding "\\x11z\\xc0[d~\\xfcK\\xb1\\xf8\\x11z\\xc0[d~" i get wrong answer 225c7831317a5c7863305b647e5c7866634b5c7862315c7866385c7831317a5c7863305b647e22dn 如果我传递的变量持有“ \\ x11z \\ xc0 [d〜\\ xfcK \\ xb1 \\ xf8 \\ x11z \\ xc0 [d〜””,我得到的答案是225c7831317a5c7863305b647e5c7866634b5c7862315c7866385c7831317a5c7863305b647e22dn

Has it got something with this assignment base64_decoded := fmt.Sprintf("%q", base64_decode) 通过此分配base64_decoded是否有东西:= fmt.Sprintf(“%q”,base64_decode)

what am i doing wrong 我究竟做错了什么

Use the following code: 使用以下代码:

doc_id := "Can35qPeFkm9Xgmp9+aj3g=="
base64_decode, err := base64.StdEncoding.DecodeString(doc_id)
if err != nil {
    log.Fatal("error:", err)
}
fmt.Println(hex.EncodeToString(base64_decode))

Directly encode the bytes in base64_decode as hex. base64_decode的字节直接编码为十六进制。

The call to fmt.Sprintf("%q", base64_decode) returns a string with the bytes escaped per Go's string literal rules. 调用fmt.Sprintf("%q", base64_decode)将返回一个字符串,其中包含根据Go的字符串文字规则转义的字节。 In the general case, the bytes in the returned string are not equal to the bytes in base64_decode . 在一般情况下,返回的字符串中的字节与base64_decode的字节不相等。 For example, the input byte 0x11 is escaped to the four bytes \\x11 . 例如,输入字节0x11被转义为四个字节\\x11

what happens is that the conversion that fmt.Sprintf("%q", base64_decode) makes to base64_decode, in this process to convert some bytes in the memory are lost. 发生的是fmt.Sprintf(“%q”,base64_decode)进行的对base64_decode的转换,在此过程中,转换了内存中的某些字节会丢失。

here you below I leave an example: https://play.golang.org/p/pdQBp7NsvQM 在这里,您在下面留下一个例子: https : //play.golang.org/p/pdQBp7NsvQM

doc_id := "Can35qPeFkm9Xgmp9+aj3g=="
var_encode := b64.StdEncoding.EncodeToString([]byte(doc_id))
fmt.Println(var_encode)
var_decode , _ := b64.StdEncoding.DecodeString(var_encode)
fmt.Println(string(var_decode))

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