[英]How to filterby with nested jsonb with sqlalchemy and postgres
I can't work out how to use SQLAlchemy to query a table that contains JSONB data.我不知道如何使用 SQLAlchemy 查询包含 JSONB 数据的表。
The JSON structure is similar to this: JSON 结构类似于:
example = {
"product": "Widget",
"version": 1,
"release_date": "2019-07-01T00:00:00.000Z",
"widget": {
"code": "ABCDEF",
"name": "my widget",
"uses": {
"rain": "yes",
"snow": "no",
"heat": "sometimes",
...
I'm trying to execute a query with this functionality:我正在尝试使用此功能执行查询:
SELECT
json AS acdata
FROM
aircraft.aircraft
WHERE json -> 'widget' -> 'uses' ->> 'rain' = 'No';
in this form:以这种形式:
widget= session.query(Widget).filter_by(rain='No').first()
I know the rain='No' isn't correct but I can't work out what should go there!我知道rain='No' 不正确,但我不知道应该去那里! The objective is to get the first Widget whose key widget.uses.rain = 'No'目标是获得第一个 Widget,其 key widget.uses.rain = 'No'
I have this definition for my Widget class我的 Widget 类有这个定义
from sqlalchemy import Column, Integer, ForeignKey
from sqlalchemy.dialects.postgresql import JSONB, UUID
class Widget(Base):
__tablename__ = 'widgets'
__table_args__ = {'schema' : 'factory'}
id = Column(UUID(as_uuid=True), primary_key=True)
json = Column(JSONB, nullable=False)
...
To access a nested jsonb
value use a tuple of keys (path index operation) and astext
to convert the value as text:要访问嵌套的jsonb
值,请使用键元组(路径索引操作)和astext
将值转换为文本:
widget = session.query(Widget).\
filter(Widget.json["widget", "uses", "rain"].astext == 'No').\
first()
The resulting query uses the #>>
operator for the path index + astext operation.结果查询使用#>>
运算符进行路径索引 + astext 操作。 You cannot use filter_by()
for this kind of predicate, as it is used for simple equality checks against attributes of a model class.您不能将filter_by()
用于这种谓词,因为它用于针对模型类的属性进行简单的相等性检查。
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