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Java:输入字段的正则表达式只有数字和逗号+空格字符

[英]Java: Regular expression for the input field only numbers and commas + space characters

There is a field that is filled with numbers or groups of numbers. 有一个字段填充数字或数字组。

After the comma must be a space! 逗号后必须是空格!

The symbol " , " and the space cannot be the beginning and / or at the end of the field 符号“ , ”和空格不能是字段的开头和/或结尾

^[\d+]{1,}([,]{1}[\s]{1}).*[\d+]$ 
- this does not work. please help to write a regular expression according to the described condition.

example

1 - ok!
2, 3 - ok!
6, 7, 4 -ok!
,5 - bad!
5 6 0 - bad!
4,5 - bad!

You could use a repeating group with a space (or \\s ) prepended. 您可以使用前置空格(或\\s )的重复组。

In your pattern you could remove the .* and match the last \\d+ inside the group. 在你的模式中你可以删除.*并匹配组内的最后一个\\d+ Then repeat the group 0+ times. 然后重复0次以上的组。

It would look like ^[\\d]{1,}([,]{1}[\\s]{1}[\\d]+)*$ 它看起来像^[\\d]{1,}([,]{1}[\\s]{1}[\\d]+)*$

Note that you don't have to put the \\d+ between square brackets or else the + would be matched literally and the quantifier {1} could be omitted: 请注意,您不必将\\d+放在方括号之间,否则+将按字面匹配,并且可省略量词{1}

^\d+(?:, \d+)*$

In Java 在Java中

String regex = "^\\d+(?:, \\d+)*$";

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