如何将cURL中的数据显示到PHP中的表中？

Question

I need to get data from a website and display in a table in my website. I am getting the data correctly but now just need to add it to a table so that it is more legible.

This is the code for some of the information I am getting:

echo "<div style='font-weight: bold;'>getProvinces</div>";

$args = array();
$args["strSessionId"] = $session;

$result = CurlFunction($args, "getProvinces");
echo '<pre>';
var_dump($result);
echo '</pre>';

And

case "getProvinces":
    {
        $Url = "https://apitest.axxess.co.za/" . 
"calls/rsapi/getProvinces.json";
        $curl->setBasicAuthentication($Username, $Password);
        $curl->setOpt(CURLOPT_SSL_VERIFYPEER, false);
        $curl->setOpt(CURLOPT_SSL_VERIFYHOST,2);
        $curl->get($Url, $d);

        break;
    }

I just need some help on how to get the above info into a table. And if possible only sections. I have attached an image to show what I am getting at the moment as well as which data I would like to have in a Table format.

Thanks

Link to complete code I am using: https://transfernow.net/923hx9h1f2er

Answer 1

Use json_decode to obtain an array representing your response data, and use a foreach loop to create key-value pairs inside a table for each data item.

The code could look like:

$jsoned = json_decode($result, true)
?>
<table>
<?php foreach ($jsoned as $k => $v) {?>
<tr><td> <?=$k?> </td><td> <?=$v?> </td></tr>
<?php } ?>

btw, <?= $var ?> is a shortcut for <? echo $var; ?> <? echo $var; ?>

Answer 2

First of all, convert your json response into an array by using json_decode() like:

// assuming `$jsonResponse` is your json response variable
$decoded = json_decode($jsonResponse,true); // here true will use return response in array format

Then, you can use your response check like:

if($decoded['intCode'] == 200){
    print_r($decoded['arrProvinceId']); // this will return you your response in array
}

now, you can you foreach() loop with html whatever you need with $decoded['arrProvinceId'] result.