学习编码，我有一个关于 IF on python 的问题

Question

So I'm learning to code on Python and have some questions about how the IF statement works here since it seems to be ignoring my elif's.

The only result I get is the last one so I tried putting other options and erasing that last one and the result is I just get no answer at all.

print('name:')
name=input()
if name=='John':
  print('Sup John')
elif name!='John':
  print('Sup stanger')

print('age?')
age=input()
if (age.isdigit())==26:
  print('Yup')
elif (age.isdigit())<=0:
  print('WUT?!')
elif (age.isdigit())>=100:
  print('Are you inmortal?')
elif (age.isdigit())<=25: #Only result I get no matter what
  print('Too young')

Answer 1

It's not ignoring your elifs. You have just misunderstood what isdigit is.

isdigit tells you whether all the characters in a string are digits or not. It does not convert a string to a digit; it returns True or False.

To convert to an integer, use int .

if int(age) == 26:
   ...

Answer 2

Since you've mentioned you're trying to learn Python, I'll be a little explicit with my answer. isdigit checks if a string is numeric or not. Let's take an example.

>>> s = "23"
>>> k = "abc"
>>> type(s)
<class 'str'>
>>> type(k)
<class 'str'>
>>> s.isdigit()
True
>>> k.isdigit()
False

In your case, the first if checks the string and gets a True and the code exists the conditional. So your code should look something like this.

print('name:')
name = input()
if name=='John':
  print('Sup John')
else:
  print('Sup stanger')

print('age?')
age = input()
if int(age) == 26:
  print('Yup')
elif int(age) <= 0:
  print('WUT?!')
elif int(age) >= 100:
  print('Are you inmortal?')
elif int(age) <= 25: #Only result I get no matter what
  print('Too young')

Hope this helps.