SQL选择除具有最高值的列之外的所有行

Question

Here's my table(blog) with all the output shown via SELECT *

I'm trying to select all execpt the highest value in the blogid column

I tried using:

SELECT *
FROM blog
WHERE blogid < MAX(blogid) 
ORDER BY createddate DESC

where I hoped it selects all values that is below the max number in blogid but this gets a error "Invalid use of group function".

any help will be appreciated

Answer 1

If you are not using group by, you will need a subquery to calculate the max value:

SELECT *
FROM blog
WHERE blogid <  (select MAX(blogid) 
                 from blog)
ORDER BY createddate DESC

Answer 2

you can use not in

SELECT *
FROM blog
WHERE blogid  not in  ( select MAX(blogid)  from blog)
ORDER BY createddate DESC

for selecting max blogid you have to use subquery

Answer 3

You can use HAVING with the nested query. Aggregates in WHERE clause may not appear unless it is in a subquery contained in a HAVING clause or a select list

SELECT *
FROM blog
HAVING blogid < (select MAX(blogid) from blog)
ORDER BY createddate DESC