Python：如何遍历词典列表并将每个词典作为值添加到具有唯一键的新词典中-无需重复

Question

Have a list of dicts. I want to add a key to each dict and append them all to one dict. How do i do this without getting repeats of the same entry into new dict?

I tried this code:

# a_list is a list of dictionaries
# category_name is a string

def make_dict(a_list, category_name=None):

    a_dict = {}

    for item in a_list:
        for i in range(0, len(a_list)):
            a_dict.setdefault(category_name + str(i+1), item)

    return a_dict

But while it creates a new name, the first object in the list is repeated for the total number of objects in the list.

{
    "Open Port 1": {
        "LocalAddress": "::",
        "LocalPort": 58448,
        "RemoteAddress": "::",
        "RemotePort": 0,
        "State": 100
    },
    "Open Port 2": {
        "LocalAddress": "::",
        "LocalPort": 58448,
        "RemoteAddress": "::",
        "RemotePort": 0,
        "State": 100
    },
    "Open Port 3": {
        "LocalAddress": "::",
        "LocalPort": 58448,
        "RemoteAddress": "::",
        "RemotePort": 0,
        "State": 100
    }, ... etc

Any ideas of how to solve this issue?

Answer 1

With the code you posted - you'll get the same key "Open Port 1" reassigned with each next dict cause the counter i is not incremented:

i = 0
for item in a_list:
    a_dict.setdefault(category_name + str(i+1), item)
return a_dict

The corrected way would be:

i = 0
for item in a_list:
    a_dict.setdefault(category_name + str(i+1), item)
    i += 1
return a_dict

But , in your simple case you may just go with dict comprehension:

a_dict = {category_name + str(i): d for i, d in enumerate(a_list, 1)}

Answer 2

Yeah got it fixed straight away.

for item in a_list:
        a_dict[(category_name + str(i))] = item
        i += 1
    return a_dict