将datetime值转换为整数

Question

I am trying to make the passed_days variable an integer, so that I can add the values. So if passed_days = 1 , passed_days should equal an integer not a datetime.

I tried converting the passed_days var to as a int like int(passed_days) . This is the current code I have now:

start_day = datetime.date(2019, 7, 11)
current_day = datetime.date.today()
passed_days = current_day - start_day
current = 183

if passed_days > datetime.timedelta(days=0):
    current = 183 + passed_days
else:
    current = 183

I need the output to be something like...184 + 2

Answer 1

To get the days represented by a timedelta , use the days property like:

passed_days.days

Testcode:

import datetime as dt

start_day = dt.date(2019, 7, 11)
current_day = dt.date.today()
passed_days = current_day - start_day

print(type(passed_days.days))
print(passed_days.days)

Results:

<class 'int'>
0