如何检查是否只选中了一个或两个复选框

Question

I have to check if one checkbox is checked or both. But the problem is, if i try my code. The site has an error ("This site doesn't work").

I tried this:

    $lw1l = $_POST['lw1l'];
    $lw1s = $_POST['lw1s'];
    $lw2l = $_POST['lw2l'];
    $lw2s = $_POST['lw2s'];

    if(isset($lw1l)){
      if(isset($lw1s)){
        $lw1 = "read / write";
      }else{
        $lw1 = "read ";
      }
    }else{
      isset($lw1s){
        $lw1 = "write";
      }
    }

    if(isset($lw2l)){
      if(isset($lw2s)){
        $lw2 = "read/ write";
      }else{
        $lw2 = "read";
      }
    }else{
      if(isset($lw2s)){
        $lw2 = "write";
      }
    }

But this doesn't work...

Would be glad if somebody could help :D

Answer 1

Here is a version that will be easier to read and maintain:

function getPermissions($key){
    $s_is_set = isset($_POST[$key."s"]);
    return isset($_POST[$key."l"])
        ? $s_is_set
            ? 'read / write'
            : 'read' 
        : 'write';
}

$lw1 = getPermissions('lw1');
$lw2 = getPermissions('lw2');

Answer 2

Don't declare variables because if user doesn't click on checkbox, the variable doesn't exist.

Try this :

if(isset($_POST['lw1l'])){
    if(isset($_POST['lw1s'])){
        $lw1 = "read / write";
    }else{
        $lw1 = "read ";
    }
}else{
    if(isset($_POST['lw1s'])){
        $lw1 = "write";
    }
}

if(isset($_POST['lw2l'])){
    if(isset($_POST['lw2s'])){
        $lw2 = "read/ write";
    }else{
        $lw2 = "read";
    }
}else{
    if(isset($_POST['lw2s'])){
        $lw2 = "write";
    }
}