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JavaScript:针对特定类型的鞋子过滤鞋子对象数组并返回索引作为属性的对象数组

[英]JavaScript: Filter Array of Shoe Objects for Specific Type of Shoes and Return Object Array with Index as Property

I have the following array of shoe objects:我有以下鞋子对象数组:

var currentInventory = [
  {
    name: 'Brunello Cucinelli',
    shoes: [
      {name: 'tasselled black low-top lace-up', price: 1000},
      {name: 'tasselled green low-top lace-up', price: 1100},
      {name: 'plain beige suede moccasin', price: 950},
      {name: 'plain olive suede moccasin', price: 1050}
    ]
  },
  {
    name: 'Gucci',
    shoes: [
      {name: 'red leather laced sneakers', price: 800},
      {name: 'black leather laced sneakers', price: 900}
    ]
  }
];

Using the currentInventory array above, I want to find all the laced shoes and indicate which word contains lace:使用上面的 currentInventory 数组,我想找到所有系鞋带并指出哪个词包含蕾丝:

Desired output below:所需的输出如下:

[
  {
    "nameWords": [
      "tasselled",
      "black",
      "low-top",
      "lace-up"
    ],
    "targetWordIndex": 3
  },
  {
    "nameWords": [
      "tasselled",
      "green",
      "low-top",
      "lace-up"
    ],
    "targetWordIndex": 3
  },
  {
    "nameWords": [
      "red",
      "leather",
      "laced",
      "sneakers"
    ],
    "targetWordIndex": 2
  },
  {
    "nameWords": [
      "black",
      "leather",
      "laced",
      "sneakers"
    ],
    "targetWordIndex": 2
  }
]

Below is my attempted code;以下是我尝试的代码; it comes close but not quite there:它接近但不完全在那里:

function renderLacedShoes(inventory) {

  //console.log(inventory)

  let finalArr = []; 


  for (let i=0; i<inventory.length; i++){
    let indObj = inventory[i];

    let newObj = {};

    // dive into values associated with shoes 

    for (let k=0; k<indObj.shoes.length; k++){
      let shoeNameArr = indObj.shoes[k].name.split(" ");    

      //console.log(shoeNameArr)

      if ( (shoeNameArr.includes('lace-up')) || (shoeNameArr.includes('laced')) ){

        newObj['nameWords'] = shoeNameArr;
        console.log(newObj)

        // not working below
        newObj['targetWordIndex'] = (shoeNameArr.indexOf('lace-up' || 'laced'))
      }
    }
    finalArr.push(newObj);
  }
  return finalArr;
}


// TEST: 
renderLacedShoes(currentInventory)

My code outputs:我的代码输出:

[ { nameWords: [ 'tasselled', 'green', 'low-top', 'lace-up' ],
    targetWordIndex: 3 },
  { nameWords: [ 'black', 'leather', 'laced', 'sneakers' ],
    targetWordIndex: -1 } ]

I see two issues: It's not returning ALL the "lace" containing shoes.我看到两个问题:它没有返回所有包含鞋子的“花边”。 Also, my targetWordIndex is off.另外,我的 targetWordIndex 已关闭。

What am I doing wrong?我究竟做错了什么?

You have not only a problem with the index, but also with the pushing the result.您不仅有索引问题,而且推送结果也有问题。 This should take place inside of the inner loop.这应该发生在内部循环内部。

 function renderLacedShoes(inventory) { let finalArr = []; for (let i = 0; i < inventory.length; i++) { let indObj = inventory[i]; for (let k = 0; k < indObj.shoes.length; k++) { let nameWords = indObj.shoes[k].name.split(" "); let targetWordIndex = nameWords.findIndex(s => s === 'lace-up' || s === 'laced'); if (targetWordIndex !== -1) { finalArr.push({ nameWords, targetWordIndex }); } } } return finalArr; } var currentInventory = [{ name: 'Brunello Cucinelli', shoes: [{ name: 'tasselled black low-top lace-up', price: 1000 }, { name: 'tasselled green low-top lace-up', price: 1100 }, { name: 'plain beige suede moccasin', price: 950 }, { name: 'plain olive suede moccasin', price: 1050 }] }, { name: 'Gucci', shoes: [{ name: 'red leather laced sneakers', price: 800 }, { name: 'black leather laced sneakers', price: 900 }] }], result = renderLacedShoes(currentInventory); console.log(result);
 .as-console-wrapper { max-height: 100% !important; top: 0; }

 let renderLacedShoes = (arr) => {
    const array = [];
    arr.forEach(elem => {
        elem.shoes.forEach(names => {
            let nameWords = names.name.split(" ");
            nameWords.forEach((elem, i) => {
                if (elem.indexOf("lace") >= 0) {
                    array.push({
                        nameWords: nameWords,
                        targetWordIndex: i
                    });
                }
            });

        });
    });
    return array;
}

You can attempt it using a chain of map and filter to reach to desired solution您可以尝试使用一系列mapfilter来达到所需的解决方案

 var res = [{ name: 'Brunello Cucinelli', shoes: [{ name: 'tasselled black low-top lace-up', price: 1000 }, { name: 'tasselled green low-top lace-up', price: 1100 }, { name: 'plain beige suede moccasin', price: 950 }, { name: 'plain olive suede moccasin', price: 1050 }] }, { name: 'Gucci', shoes: [{ name: 'red leather laced sneakers', price: 800 }, { name: 'black leather laced sneakers', price: 900 }] }] .map(d => d.shoes.map(r => r.name)).flat() .filter(d => d.includes('lace')) .map(d => ({ nameWords: d.split(' '), targetWordIndex: d.split(' ').findIndex(d => d.includes('lace'))})) console.log(res)

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