[英]Map Update method with ifAbsent in Dart
I'd like to modify an existing item in a map, as in replace the value of an existing key with a new one, with an added clause if the key does not exist in the Map already, to simply create a new key and value pair.我想修改地图中的现有项目,例如用新键替换现有键的值,如果键在地图中不存在,则添加一个子句,以简单地创建新键和值一对。 The Dart documentation suggests the update method for such a purpose, but I'm not quite sure about how to implement it with the optional ifAbsent() parameter, which I assume is a line of code called if the key to be updated does not exist.
Dart 文档为此目的建议了更新方法,但我不太确定如何使用可选的 ifAbsent() 参数来实现它,我假设这是一行代码,如果要更新的密钥不存在.
V update(K key, V update(V value), {V ifAbsent()});
According to the documentation, there is an optional parameter to be taken, but it shows an error saying too many parameters, 2 expected but 3 found.根据文档,有一个可选参数要采用,但它显示一个错误,说参数太多,需要 2 个,但找到 3 个。
This shows no error (not yet tested, but theoretically should work):这显示没有错误(尚未测试,但理论上应该可以工作):
userData.update(key, value);
This (with the added create if not exist clause) does:这(添加了 create if not exist 子句)执行以下操作:
userData.update(key, value,
userData[key] = value;
);
Any help to get the latter or equivalent to work is much appreciated!非常感谢获得后者或等效于工作的任何帮助! I assume I'm missing something rather obvious here...
我想我在这里遗漏了一些相当明显的东西......
That is a named parameter, you can use it like this:这是一个命名参数,您可以像这样使用它:
userData.update(
key,
// You can ignore the incoming parameter if you want to always update the value even if it is already in the map
(existingValue) => value,
ifAbsent: () => value,
);
Updates the value for the given key.更新给定键的值。
user["age"] = 25;
user.update("age", (dynamic val) => ++val); // => 26
This also returns the new value.这也会返回新值。 To prevent an error being thrown should the key not exist, there's a third parameter:
为了防止在键不存在时抛出错误,还有第三个参数:
user.update("name", (dynamic val) => "Jim", ifAbsent: () => "Jane");
print(user); // => {"age": 26, "name": "Jane"};
In most cases you could update using the array bracket notation:在大多数情况下,您可以使用数组括号表示法进行更新:
user["name"] = "Mary";
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